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multiplication and div.

 
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ccs_guest
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multiplication and div.
PostPosted: Thu Jul 30, 2009 11:38 pm     Reply with quote

Hi all,

Consider the following scenario.
Code:

int32 tmp1;
float a;
tmp1=-33862;
a=(float)tmp1/1000000000;

The value in a should be should be -0.00003386 but a=4.294934.
If I do
Code:
 a=tmp1/1000000000;

then a=4.000000

What is wrong?
Thnx...
PCM programmer



Joined: 06 Sep 2003
Posts: 21708

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PostPosted: Fri Jul 31, 2009 12:20 am     Reply with quote

Quote:
int32 tmp1;
float a;

tmp1=-33862;

In CCS, all integer data types are unsigned by default. To declare tmp1
as signed, you need to do this:
Code:
signed int32 tmp1;
ccs_guest
Guest







multiplication and div.
PostPosted: Fri Jul 31, 2009 12:44 am     Reply with quote

After making tmp as signed, a is having -0.00000;
PCM programmer



Joined: 06 Sep 2003
Posts: 21708

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PostPosted: Fri Jul 31, 2009 12:50 am     Reply with quote

Which 'a' ? The first one, or the 2nd one ?

The first expression is doing floating point math, and the 2nd one is
doing integer math.

Always make a test program and always post it (along with your compiler
version). The program shown below displays the following results:
Quote:

a = -0.000033862
a = 0.000000000


Code:
#include <16F877.H>
#fuses XT, NOWDT, NOPROTECT, BROWNOUT, PUT, NOLVP
#use delay(clock=4000000)
#use rs232(baud=9600, xmit=PIN_C6, rcv=PIN_C7, ERRORS)

//======================================
void main()
{
signed int32 tmp1;
float a;

tmp1=-33862;

a=((float)tmp1)/1000000000.0;
printf("a = %10.9f \r", a);

a=tmp1/1000000000;
printf("a = %10.9f \r", a);

while(1);
}
Guest








PostPosted: Fri Jul 31, 2009 12:57 am     Reply with quote

Quote:

a=((float)tmp1)/1000000000.0;

That solved my problem.
Thanks a lot.
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