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MCP3208 problem

 
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pfo
Guest







MCP3208 problem
PostPosted: Tue Dec 02, 2003 11:39 am     Reply with quote

convert_to_voltage() works, the mcp3208 also works right, but y the hell isnt the result in the range fron 0 to 4096 (mcp3208 has 12bit) ...


thx!






#include <16F877.h>
#fuses HS,NOWDT,NOPROTECT,NOLVP
#use delay(clock=20000000)
#use rs232(baud=9600, xmit=PIN_C6, rcv=PIN_C7) // Jumpers: 8 to 11, 7 to 12

#include <MCP3208.C>

void display_data(unsigned long data ) {


printf(" (%ld)",data);
}


void main() {
unsigned long value=0;

adc_init();

printf("Sampling:\r\n");

do {


value = read_analog(0); //channel 0 single mode (ADXL_X)
printf("\n\rCh0: ");
printf(" %ld",value);

value = read_analog(1); //channel 0 single mode (ADXL_Y)
printf(" Ch1: ");
printf(" %ld",value);

} while (TRUE);

}


the result looks like this:


Ch0: 32240 Ch1: -28256
Ch0: 32240 Ch1: -28240
Ch0: 32240 Ch1: -28240
Ch0: 32240 Ch1: -28240
Ch0: 32240 Ch1: -28240
Ch0: 32240 Ch1: -28256
Ch0: 32240 Ch1: -28256
Ch0: 32240 Ch1: -28256
Ch0: 32240 Ch1: -28240
Ch0: 32240 Ch1: -28256
Ch0: 32240 Ch1: -28256
Ch0: 32240 Ch1: -28240
Ch0: 32240 Ch1: -28256
Ch0: 32240 Ch1: -28240
Ch0: 32240 Ch1: -28240
Ch0: 32240 Ch1: -28240
Ch0: 32240 Ch1: -28240
Ch0: 32240 Ch1: -28240
Ch0: 32240 Ch1: -28256
Ch0: 32240 Ch1: -28256
Ch0: 32240 Ch1: -28240
Ch0: 32240 Ch1: -28240
Ttelmah
Guest







Re: MCP3208 problem
PostPosted: Tue Dec 02, 2003 11:51 am     Reply with quote

pfo wrote:
convert_to_voltage() works, the mcp3208 also works right, but y the hell isnt the result in the range fron 0 to 4096 (mcp3208 has 12bit) ...


thx!






#include <16F877.h>
#fuses HS,NOWDT,NOPROTECT,NOLVP
#use delay(clock=20000000)
#use rs232(baud=9600, xmit=PIN_C6, rcv=PIN_C7) // Jumpers: 8 to 11, 7 to 12

#include <MCP3208.C>

void display_data(unsigned long data ) {


printf(" (%ld)",data);
}


void main() {
unsigned long value=0;

adc_init();

printf("Sampling:\r\n");

do {


value = read_analog(0); //channel 0 single mode (ADXL_X)
printf("\n\rCh0: ");
printf(" %ld",value);

value = read_analog(1); //channel 0 single mode (ADXL_Y)
printf(" Ch1: ");
printf(" %ld",value);

} while (TRUE);

}


the result looks like this:


Ch0: 32240 Ch1: -28256
Ch0: 32240 Ch1: -28240
Ch0: 32240 Ch1: -28240
Ch0: 32240 Ch1: -28240
Ch0: 32240 Ch1: -28240
Ch0: 32240 Ch1: -28256
Ch0: 32240 Ch1: -28256
Ch0: 32240 Ch1: -28256
Ch0: 32240 Ch1: -28240
Ch0: 32240 Ch1: -28256
Ch0: 32240 Ch1: -28256
Ch0: 32240 Ch1: -28240
Ch0: 32240 Ch1: -28256
Ch0: 32240 Ch1: -28240
Ch0: 32240 Ch1: -28240
Ch0: 32240 Ch1: -28240
Ch0: 32240 Ch1: -28240
Ch0: 32240 Ch1: -28240
Ch0: 32240 Ch1: -28256
Ch0: 32240 Ch1: -28256
Ch0: 32240 Ch1: -28240
Ch0: 32240 Ch1: -28240


It looks as though the result is being 'left justified' (shifted to the upper end of the 16 bit value), rather than right justified.
I think you will see that the read function, actually shifts the data left four bits.
Try:
value=read_analog(0)>>4;

Best Wishes
PCM programmer



Joined: 06 Sep 2003
Posts: 21708

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PostPosted: Tue Dec 02, 2003 2:08 pm     Reply with quote

The functions in MCP3208.C return unsigned 16-bit numbers.
(All CCS integer data types are unsigned by default -- unlike normal C).

So in your printf statements, you need to use %lu instead of %ld.
--------------------

I'm looking at the CCS manual.

In the Jan 2003 manual, right below the Type Specifier chart, they
had this statement:
All types, except float, by default are unsigned; however, [they]
may be preceded by unsigned or signed.


But they don't have that statement in the current manual (May 2003).

This is going to screw up newbies big time.

They haven't changed the compiler. It still has an int or "long int"
as unsigned by default.
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