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Two dimensional arrays for strings

 
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csanders



Joined: 23 Apr 2005
Posts: 16

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Two dimensional arrays for strings
PostPosted: Mon Dec 11, 2006 9:59 pm     Reply with quote
I am trying to create an error log in memory using a 2 dimensional array to store a verbose message, but cannot get the code to compile.

Code:

char errorlog[10][20];
int8 index;

//on error, place error message in array
if (index < 18)
{
   errorlog[index++][0] = "error msg";   //compilation error occurs here
}


Does anyone know what I am doing wrong?

Thanks
treitmey



Joined: 23 Jan 2004
Posts: 1094
Location: Appleton,WI USA

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PostPosted: Mon Dec 11, 2006 10:20 pm     Reply with quote
This is what I do. Perhaps it is that I use const char??
replace STDERR with any stream you've defined.
Code:
const char error_txt[16][16] =
{
  "USART overflow",  // -0-
  "TXBuffer ovrflw", // -1-
  "RXBuffer ovrflw", // -2-
  "Bad Checksum",    // -3-
  "LCD busy",        // -4-
  "5",  // -5-
  "6",  // -6-
  "7",
  "8",
  "9",
  "10",
  "11",
  "12",
  "13",
  "14",
  "NO ERRORS"
};

//somewhere else in code
bit_set(ERRORS,1);//set error flag bit 1 for tx overflow

unsigned int16 ERRORS;



void ChkErr(void) //print out any errors that occured
{
  int8 chk=0;
  if (ERRORS==0){return;} //if no errors jump right back out
  for(chk=0;chk<16;chk++)
  {
    if (bit_test(ERRORS,chk))
    {
      bit_clear(ERRORS,chk);
      fprintf(STDERR,"ERROR(%U): %s.\r\n",chk,error_txt[chk]);
      tx_buffer(NACK,sizeof(NACK));
      rx_indx_i=rx_indx_o=0;
    }
  }
}
Ttelmah
Guest
PostPosted: Tue Dec 12, 2006 3:16 am     Reply with quote
To load data from a 'constant' string, into the array, you need to use 'memcpy' or 'strcpy'. So:
Code:

   strcpy(&errorlog[index++][0],"error msg");

You can't just 'hand' a string into the array.
As a separate comment, what is going to happen when index is greater than 9?. You are trapping it at 18, but the array dimension on this axis, only goes 0..9.

Best Wishes
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