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Problem declaring a pointer

 
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Wizard



Joined: 27 Mar 2006
Posts: 9

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Problem declaring a pointer
PostPosted: Wed Mar 29, 2006 4:22 pm     Reply with quote
I have no idea why I can't compile the following var declaration, I'm going to use it to display a menu in a LCD.
Code:

char *menu[]=
{
   " Start/Stop  Sample",
   "Show  Atmosph. Temp.",
   "Show  Corporal Temp.",
   "  Sample Settings",
   "  System Settings"
};

I got the "Expect }" error from the compiler, the compiler stuck after ...Sample",
Any ideas? I would say that the C sintax it's rather than correct.
Does someone know a equivalent code which will compile?
I have planed to use the var like this:
Code:

lcd_gotoxy(1,(i+1));
print_lcd(menu[command]);

Thanks,
_________________
Tomas L.
PCM programmer



Joined: 06 Sep 2003
Posts: 21708

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PostPosted: Wed Mar 29, 2006 4:37 pm     Reply with quote
The program shown below has the following output:
Code:

Start/Stop  Sample

Show  Atmosph. Temp.

Show  Corporal Temp.

  Sample Settings   

  System Settings   


Code:
#include <18F452.h>
#fuses XT,NOWDT,PUT,BROWNOUT,NOPROTECT,NOLVP
#use delay(clock=4000000)
#use rs232(baud=9600, xmit=PIN_C6, rcv=PIN_C7, ERRORS)

char *menu[5][21]=
{
  {" Start/Stop  Sample "},
  {"Show  Atmosph. Temp."},
  {"Show  Corporal Temp."},
  {"  Sample Settings   "},
  {"  System Settings   "}
};

//============================
void main()
{
int8 i;

for(i = 0; i < 5; i++)
    printf("%s\n\r", menu[i]);

while(1);
}
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