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Message |
Wizard
Joined: 27 Mar 2006 Posts: 9
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Problem declaring a pointer |
Posted: Wed Mar 29, 2006 4:22 pm |
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I have no idea why I can't compile the following var declaration, I'm going to use it to display a menu in a LCD.
Code: |
char *menu[]=
{
" Start/Stop Sample",
"Show Atmosph. Temp.",
"Show Corporal Temp.",
" Sample Settings",
" System Settings"
};
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I got the "Expect }" error from the compiler, the compiler stuck after ...Sample",
Any ideas? I would say that the C sintax it's rather than correct.
Does someone know a equivalent code which will compile?
I have planed to use the var like this:
Code: |
lcd_gotoxy(1,(i+1));
print_lcd(menu[command]);
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Thanks, _________________ Tomas L. |
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PCM programmer
Joined: 06 Sep 2003 Posts: 21708
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Posted: Wed Mar 29, 2006 4:37 pm |
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The program shown below has the following output:
Code: |
Start/Stop Sample
Show Atmosph. Temp.
Show Corporal Temp.
Sample Settings
System Settings
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Code: | #include <18F452.h>
#fuses XT,NOWDT,PUT,BROWNOUT,NOPROTECT,NOLVP
#use delay(clock=4000000)
#use rs232(baud=9600, xmit=PIN_C6, rcv=PIN_C7, ERRORS)
char *menu[5][21]=
{
{" Start/Stop Sample "},
{"Show Atmosph. Temp."},
{"Show Corporal Temp."},
{" Sample Settings "},
{" System Settings "}
};
//============================
void main()
{
int8 i;
for(i = 0; i < 5; i++)
printf("%s\n\r", menu[i]);
while(1);
} |
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