16F628 e2p writing problem

[Invisible]

hi,

just little problem with a 16F628, if I call this piece of code:

void write_e2p() {
for (i=0;i<=9;++i) {
write_eeprom(i,0x10);
printf("add: \%u=\%u,i,read_eeprom(i));
}
}

when reading e2p I got
add: 0=255
add: 1=255
...and so,
what is the problem here?, eeprom is suposed to be 10h in all that addreses..

best regards
Invisible
___________________________
This message was ported from CCS's old forum
Original Post ID: 10884

[kolio]

:=hi,
:=
:=just little problem with a 16F628, if I call this piece of code:
:=
:=void write_e2p() {
:= for (i=0;i<=9;++i) {
:= write_eeprom(i,0x10);
:= printf("add: \%u=\%u,i,read_eeprom(i));
:= }
:= }
:=
:=when reading e2p I got
:=add: 0=255
:=add: 1=255
:=...and so,
:=what is the problem here?, eeprom is suposed to be 10h in all that addreses..
:=
:=best regards
:=Invisible

Oups,
in write_eeprom(i,0x10) first parameter is the value and the second is the address, so just swap their places in the souce code. It should work. It is normal that you're reading 255 - the eeprom is clear, but if you're try to read from address 0x10 there will be 9
Wish you luck!
___________________________
This message was ported from CCS's old forum
Original Post ID: 10885

[Invisible]

hi,

I just need a glases to read correctly the help file,
thanks for your help!

best regards
Invisible
___________________________
This message was ported from CCS's old forum
Original Post ID: 10894