array problem

[ferrarilib]

#rom 0x2100 = {0x4F, 0x4B, 0x00, 0x42, 0x55, 0x53, 0x59, 0x00}

..........


char* Read_E(long int EX)
{
char* buffer; // this do problem
//char buffer[10]; // this is good
int count;
int index_ex;

index_ex = EX;
count = 0;

do {
buffer[count] = read_EEPROM(index_ex++);
}while(buffer[count++] != 0x00);

return (buffer);

}

main()
{
printf(lcd_putc,"\f%s",Read_E(0));
while(1);
}


this is my problem.
if i do char *buffer the printf return samething not good, but if i do char buffer[10] return OK

where i do samething not good ?

thanks

[Ttelmah]

The problem here is, 'where is the buffer'...
The declaration:
char* buffer;

Means declare 'buffer', to be a pointer to a memory area. It does not assign any actual memory to _hold_ the data (except the pointer itself).
You then go and write data to the address referenced by this pointer, which can be anywhere in memory - no wonder it does not work....
If you did this on a processor that had a memory management chip (like a PC), you would get an exception error raised as soon as you tried to do this, that the program was attempting to access memory it shouldn't. Without this hardware protetion on the PIC, all you will get is data being destroyed...
You need to make a call to 'malloc' (with stdlibm loaded) to actually allocate some memory for 'buffer' to address.

Best Wishes

[ferrarilib]

THANKS Ttelmah .