Convert '1' to 49, 'B' to 66 ...

[METsai]

Hi

Does anyone know how to convert ascii to number, ex: '1' to 49,

'D' to 68, 'i' to 105, 'u' to 117 ... Does CCS provide this function?

Or someone knows how to do that?

Thank you for your help.

[PCM programmer]

Download the CCS manual:
http://www.ccsinfo.com/downloads/ccs_c_manual.pdf
Look in the section on the printf() function (page 196 in the Acrobat
reader). Look at the format specifiers. You want to display ASCII
values as decimal integers (or unsigned decimal integers). Which
format specifier listed in the CCS manual will allow you to do this ?
The answer is on that page.

[METsai]

Thank you for your help.

But I do not printf it.

I know printf can print ascii code,

char mystring;
mystring = 'D';
printf("mystring = %d", mystring);

>> mystring =68

But I want to use it. For example, I give PIC 'A', PIC converts 'A' to 65.

Then I give PIC 'g', PIC converts 'g' to 103. Then I can use 65, 103 for

more applications. Is it possible?

Thank you for your help.

[PCM programmer]

Use the atoi() function. It's in the manual. You need to #include
the stdlib.h file in your program to use it.

[Zei]

I'm not sure if I understood this right but could you use just simple int8 number = 'A'; and number is now 65?

[Ttelmah]

Yes.

This is exactly the point. If you receive a character on the serial port for instance, what is stored in the processor, is just the number. It only 'becomes' the character, when you output it again.
So:

[John676]

Hi,

Not 100% sure of what your doing, '1' is already 49.

If you mean how do you take '1' and turn it into "49" to output like that then:

char NumberToConvert;
char Result[3];
char Buffer;

NumberToConvert= '1'; // '1' = 49 = 0x31

Buffer = (NumberToConvert - (NumberToConvert % 100)) / 100;
Result[0] = Buffer + 0x30;

NumberToConvert = NumberToConvert - Buffer;
Buffer = (NumberToConvert - (NumberToConvert % 10)) / 10;
Result[1] = Buffer + 0x30;

NumberToConvert = NumberToConvert - (Buffer * 10);
Result[2] = NumberToConvert + 0x30;

// Result will have '0' and '4' and '9'

// another example


NumberToConvert= 'm'; // 'm' = 109 = 0x6D

Buffer = (NumberToConvert - (NumberToConvert % 100)) / 100;
Result[0] = Buffer + 0x30;

NumberToConvert = NumberToConvert - Buffer;
Buffer = (NumberToConvert - (NumberToConvert % 10)) / 10;
Result[1] = Buffer + 0x30;

NumberToConvert = NumberToConvert - (Buffer * 10);
Result[2] = NumberToConvert + 0x30;

// Result will have '1' and '0' and '9'

Let know if this is what you wanted.

NumberToConvert can be set to any value between 0 and 999.

[METsai]

Thank you for your help.

Your code helps me a lot.

But there is a strange situation.

When NumberToConvert is '0' ~ 'c', your code works fine.

When NumberToConvert is 'd', Result has '1' and '9' and '9'.

When NumberToConvert is 'e', Result has '1' and ':' and '0'.

When NumberToConvert is 'f', Result has '1' and ':' and '1'.

When NumberToConvert is 'g', Result has '1' and ':' and '2'.

.....

It seems NumberToConvert only can be set to any value between 0 and 99.

Could you help this problem?

Thank you very much.