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rwskinner
Joined: 08 Dec 2006
Posts: 125
Location: Texas
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| Newbie - Assigning values to array during runtime |
 Posted: Sun Dec 10, 2006 3:41 pm |
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int buffer[8]
Can I assign values at run time like this?
buffer = {1,2,3,4,5,6,7,8};
I do I have to do it long hand
buffer[0] = 1;
buffer[1] = 2;
....
Sorry, new to C and I know I can set the values during compile time when I declare the var but I didn't know of an easy way during runtime. |
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PCM programmer
Joined: 06 Sep 2003
Posts: 21708
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| Posted: Sun Dec 10, 2006 3:59 pm |
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| Quote: |
Can I assign values at run time like this?
buffer = {1,2,3,4,5,6,7,8};
do I have to do it long hand
buffer[0] = 1;
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You could copy a constant array to the RAM buffer with the memcpy()
function. I tested this with PCH vs. 3.249 and it works. Here's the
output of the program shown below:
| Quote: |
01 02 03 04 05 06 07 08
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| Code: |
#include <18F452.h>
#fuses HS, NOWDT, PUT, BROWNOUT, NOLVP
#use delay(clock=20000000)
#use rs232(baud=9600, xmit=PIN_C6, rcv=PIN_C7, ERRORS)
char const data[8] = {1,2,3,4,5,6,7,8};
//======================================
main(void)
{
int8 i;
int8 buffer[8];
// Copy the constant array to the RAM array.
memcpy(buffer, data, sizeof(data));
// Display the contents of the RAM array.
for(i = 0; i < sizeof(buffer); i++)
printf("%X ", buffer[i]);
while(1);
} |
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