ATOI() Won't Convert Hex To Int8

[DonWare]

I really did look around here for a solution to this
problem before I posted but...

If I run this code I get X=0.
If I use onle decimal characters it works OK.

int1 temp;
char tmp_buff[15];

int8 x;

tmp_buff[0]='F';
tmp_buff[1]=0;

x=atoi(tmp_buff);

What am I doing wrong ?
The goal is to convert two incoming ASCII checksum characters into int8.
An alternate method idea is welcomed.

Thanks in advance.
Don

[rwyoung]

From good, ole Unix man pages:

The atoi(), atol(), strtol(), and strtoul() functions are used to convert a
character string pointed to by the nptr parameter to an integer having a
specified data type. The atoi() and atol() functions convert a character
string containing decimal integer constants, but the strtol() and strtoul()
functions can convert a character string containing a integer constant in
octal, decimal, hexadecimal, or a base specified by the base parameter.


Check to see if strtol() and strtoul() exist in the CCS compiler documentation. Otherwise consider writing your own.
_________________
Rob Young
The Screw-Up Fairy may just visit you but he has crashed on my couch for the last month!

[DonWare]

The ccs manual says "Accepts both decimal and hexadecimal argument"

I entered the example form the manual and it worked ok - except for hex input.

Thanks.

[PCM programmer]

You're giving atoi a string of "F".

How does atoi know that this is a hex digit ?

Look in the source code for atoi(), which is in stdlib.h
(Look it c:\Program Files\PICC\drivers)

It's looking for "0x" to be in front of the hex string:

[DonWare]

I tried 0x and had no luck.

What I've decided to do is use isalpha() or isdigit() and go from there for each character.

Thanks.

[DonWare]

I tried 0X again and it worked. Who knows what I did wrong before.

I didn't know code was available for the built in functions.

Thanks alot !!!