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character lookup table access

 
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The Puma



Joined: 23 Apr 2004
Posts: 227
Location: The Netherlands

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character lookup table access
PostPosted: Tue Mar 14, 2006 2:44 pm     Reply with quote

How can i get a character in the character table

I would have a write routine that writes a string to a led board
This routine must get the character from this table

Code:
int const Font[96][5] = {
   {0x00, 0x00, 0x00, 0x00, 0x00 ,}   // 0x20, Space
   {0x00, 0x00, 0x5F, 0x00, 0x00 ,}   // 0x21, !
   {0x00, 0x07, 0x00, 0x07, 0x00 ,}   // 0x22, "
   {0x14, 0x7F, 0x14, 0x7F, 0x14 ,}   // 0x23, #
   {0x24, 0x2A, 0x7F, 0x2A, 0x12 ,}   // 0x24, 0x
   {0x23, 0x13, 0x08, 0x64, 0x62 ,}   // 0x25, %
   {0x36, 0x49, 0x55, 0x22, 0x50 ,}   // 0x26, &
   {0x00, 0x05, 0x03, 0x00, 0x00 ,}   // 0x27, '
   {0x00, 0x1C, 0x22, 0x41, 0x00 ,}   // 0x28, (
   {0x00, 0x41, 0x22, 0x1C, 0x00 ,}   // 0x29, )
   {0x08, 0x2A, 0x1C, 0x2A, 0x08 ,}   // 0x2a, *
   {0x08, 0x08, 0x3E, 0x08, 0x08 ,}   // 0x2b, +
   {0x00, 0x50, 0x30, 0x00, 0x00 ,}   // 0x2c, ,
   {0x08, 0x08, 0x08, 0x08, 0x08 ,}   // 0x2d, -
   {0x00, 0x60, 0x60, 0x00, 0x00 ,}   // 0x2e, .
   {0x20, 0x10, 0x08, 0x04, 0x02 ,}   // 0x2f, /
   {0x3E, 0x51, 0x49, 0x45, 0x3E ,}   // 0x30, 0
   {0x00, 0x42, 0x7F, 0x40, 0x00 ,}   // 0x31, 1
   {0x42, 0x61, 0x51, 0x49, 0x46 ,}   // 0x32, 2
   {0x21, 0x41, 0x45, 0x4B, 0x31 ,}   // 0x33, 3
   {0x18, 0x14, 0x12, 0x7F, 0x10 ,}   // 0x34, 4
   {0x27, 0x45, 0x45, 0x45, 0x39 ,}   // 0x35, 5
   {0x3C, 0x4A, 0x49, 0x49, 0x30 ,}   // 0x36, 6
   {0x01, 0x71, 0x09, 0x05, 0x03 ,}   // 0x37, 7
   {0x36, 0x49, 0x49, 0x49, 0x36 ,}   // 0x38, 8
   {0x06, 0x49, 0x49, 0x29, 0x1E ,}   // 0x39, 9
   };
PCM programmer



Joined: 06 Sep 2003
Posts: 21708

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PostPosted: Wed Mar 15, 2006 12:30 am     Reply with quote

Study the C language topic of "two dimensional arrays":
http://www.eskimo.com/~scs/cclass/int/sx9.html
http://www.macdonald.egate.net/CompSci/harray2.html
The Puma



Joined: 23 Apr 2004
Posts: 227
Location: The Netherlands

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PostPosted: Thu Mar 16, 2006 9:52 am     Reply with quote

Thx PCM,

Bot now i which to pass a string to the routine, and this string must be displayed.

How must i change below source?

Code:
void hcms2911_send_byte(int data) {
   int i;

   for(i=0;i<8;i++) {
      output_bit(HCMS2911_DIN,data & 0x80);
      output_high(HCMS2911_CLK);
      delay_cycles(2);
      output_low(HCMS2911_CLK);
      data=data<<1;
   }
}

void hcms2911_put(int data) {
   output_low(HCMS2911_RS);
   output_low(HCMS2911_CE);
   hcms2911_send_byte(data);
   output_high(HCMS2911_CE);
   output_low(HCMS2911_CLK);
}

void readfont(int ccode) {
   int cidx;

   if(Ccode>=0x20&&Ccode<0x80)
      Ccode-=0x20;
   
   for(cidx=0;cidx<5;cidx++)
      hcms2911_put(Font[Ccode][cidx]);
}


#include <18F4620.h>
#use delay(clock=20000000)
#fuses HS,NOWDT,NOBROWNOUT,NOPUT,NOLVP,DEBUG,NOSTVREN,NOPROTECT

#include <hcms2911.h>

void main() {

   int i;

   hcms2911_init();

   while (1) {
      for(i=0x20;i<0x80;i++) {
      readfont(i);
      delay_ms(150);
      }
   }
}
ckielstra



Joined: 18 Mar 2004
Posts: 3680
Location: The Netherlands

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PostPosted: Thu Mar 16, 2006 11:47 am     Reply with quote

Quote:
Bot now i which to pass a string to the routine, and this string must be displayed.
The CCS compiler has a nice addition to the printf command allowing you to assign a function for processing the data one character at a time.

This should do the trick
Code:
printf(readfont, "It works!");
The Puma



Joined: 23 Apr 2004
Posts: 227
Location: The Netherlands

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PostPosted: Thu Mar 16, 2006 12:10 pm     Reply with quote

It displays the whole message.
But the message must routating from left to right
ckielstra



Joined: 18 Mar 2004
Posts: 3680
Location: The Netherlands

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PostPosted: Thu Mar 16, 2006 12:47 pm     Reply with quote

How do you expect us to know you want a rotating message? We can't read your mind.

You have most pieces of the puzzle, just add a rotating mechanism. Shouldn't be very difficult to create such a thing but I'm not going to do it for you unless you have shown some effort yourself first.
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