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Guest
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| mm:ss:dd subtraction ? |
 Posted: Tue Aug 30, 2005 1:31 am |
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I have a number of mm:ss:dd where mm is minutes, ss is second and dd is tenth of second, my problem is subtraction to 8? that is es:
01:32:01 - 00:00:08 = xx:xx:xx
02:01:05 - 00:00:08 = xx:xx:xx
............ - 00:00:08 = xx:xx:xx
As I can make subtraction? |
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MikeValencia
Joined: 04 Aug 2004
Posts: 238
Location: Chicago
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| Re: mm:ss:dd subtraction ? |
| Posted: Tue Aug 30, 2005 5:56 am |
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| Anonymous wrote: | I have a number of mm:ss:dd where mm is minutes, ss is second and dd is tenth of second, my problem is subtraction to 8? that is es:
01:32:01 - 00:00:08 = xx:xx:xx
02:01:05 - 00:00:08 = xx:xx:xx
............ - 00:00:08 = xx:xx:xx
As I can make subtraction? |
Make the following math operation:
((1 * 60 * 60) + (32 * 60) + 1) - 8
This will give you the number of seconds (a very big number)
Then convert the big number back to hh:mm:ss
Think first of the math on how you would do it. Then write the corresponding source code. |
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Guest
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| Posted: Tue Aug 30, 2005 6:11 am |
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| thanks very much! |
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Mark
Joined: 07 Sep 2003
Posts: 2838
Location: Atlanta, GA
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| Posted: Tue Aug 30, 2005 6:16 am |
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From math class:
| Code: |
signed int8 minutes, seconds, tenths;
// Init some values
minutes = 1;
seconds = 32;
tenths = 1;
// Subtract the 8
tenths -= 8;
// See if we need to borrow 1
if (tenths < 0)
{
// We did so add 1 or 10 tenths
tenths += 10;
// Borrow it
seconds--;
// Do we need to borrow a minute?
if (seconds < 0)
{
// Yep, so do it
seconds += 60;
minutes--;
// Maybe you want to check for negative here!
}
} |
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