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Message |
Jurgens Schmidt
Guest
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| button block and unblock |
 Posted: Thu May 12, 2005 9:22 am |
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I have to block user actions within 5 hours.
User enters some number on keypad and after last hitting on the "enter"
block no_press should be active.
After 5 hours you can enter the new number.
Main problem is that all other buttons ( alarm, cooler ) and so on, must be
active all the time ( and within 5 hours ). Just the enter is blocked.
How to make this ?
Timer for counting is timer0. |
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DragonPIC
Joined: 11 Nov 2003
Posts: 118
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| Posted: Thu May 12, 2005 11:05 am |
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set a flag and use an if statment everywhere the button is to be used to execute a function. Use a timer to keep track of time for 5 hours. Reset the timer when after "enter" is pressed and when time is up clear the flag to allow presses again.
| Code: | if(block_init)
nopress = 1;
if(count == hrs)
nopress = 0;
if(nopress == 0)
do_function();
else
block_function(); //in case you want to send message "blocked" to the LCD display or something. |
You can still pick up the button press and just ignore the function it is supposed to execute. Or you could use the flag to ignore the selected button press detection. You fill in the blank.
_________________
-Matt |
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Jurgens
Guest
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| Posted: Fri May 13, 2005 6:21 am |
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Thank you for your explanation.
A have some problems whit this one....
| Code: |
//Timer0
if (hour < 5)
{
blockEnterTime=1;
}
// button
if(blockEnterTime == 1)
{
printf(lcd_putc,"Block");
delay_ms(1000);
blockEnterButton=1;
}
if (blockEnterButton == 1)
{
printf(lcd_putc,"\f NO PRESS");
else
printf(lcd_putc,"\f FREE PRESS");
// do something
}
break; |
//-----------
It is ok but wenn i hit next time on the enter button, program goes thru same stuff but he should block the next enter button press...
Time is still under 5 hours and block should be activated...
I get this on the second pass : enter press / "block" / "FREE PRESS"... instead "NO PRESS"
Why is this so ? |
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Jurgens
Guest
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| Posted: Fri May 13, 2005 6:22 am |
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Thank you for your explanation.
A have some problems whit this one....
| Code: |
//Timer0
if (hour < 5)
{
blockEnterTime=1;
}
// button
if(blockEnterTime == 1)
{
printf(lcd_putc,"Block");
delay_ms(1000);
blockEnterButton=1;
}
if (blockEnterButton == 1)
{
printf(lcd_putc,"\f NO PRESS");
else
printf(lcd_putc,"\f FREE PRESS");
// do something
}
break; |
//-----------
It is ok but wenn i hit next time on the enter button, program goes thru same stuff but he should block the next enter button press...
Time is still under 5 hours and block should be activated...
I get this on the second pass : enter press / "block" / "FREE PRESS"... instead "NO PRESS"
Why is this so ? |
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bfemmel
Joined: 18 Jul 2004
Posts: 40
Location: San Carlos, CA.
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| Posted: Fri May 13, 2005 9:20 am |
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Jurgen,
Somewhere in your program you have a spot where you get new key states, at least it would be nice if there was only one place. If so then you can control which keys get reported from there. Set up a timer and set it when the enter key is pressed and don't return the ENTER key value until the timer hits zero again. See the code fragments I put together below.
| Code: |
#int_TIMER2
void TIMER2_isr( void ) {
if (lastEnterTime) // decrements the counter to keep Enter key from being seen
--lastEnterTime; // stop decrementing at 0, don't allow underflow
}
/* get physical key press information from hardware */
unsigned int8 GetNewKeyState(void) {
// .. do some sort of hardware decode to get the physical keypress
}
/* process key press */
unsigned int8 KeyPress(void) {
int8 keyReturn; // key that was pressed
if( !(keyReturn = GetNewKeyState()) ) { // As long as a key was pressed process the information
switch (keyReturn) { // allows different processing for each switch case.
case ONE:
case TWO:
case THREE:
case FOUR:
case FIVE:
case SIX:
case SEVEN:
case EIGHT:
case NINE:
case ZERO:
break;
case ENTER:
if (lastEnterTime) // As long as it has not been five minutes since the last time.
keyReturn = 0; // then return a NULL key press
else // if the five minute timer is zero, then ...
lastEnterTime = FIVE_MINUTES; // set the timer to five minutes again and return the enter key
break;
default:
keyReturn = 0;
break;
} /* end of switch */
} /* end of keyReturn not blank */
} /* end of KeyPress() */
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Good Luck;
- Bruce |
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Guest
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| Posted: Fri May 13, 2005 12:07 pm |
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| Jurgens wrote: | | Code: |
if (blockEnterButton == 1)
{
printf(lcd_putc,"\f NO PRESS");
else
printf(lcd_putc,"\f FREE PRESS");
// do something
}
break; |
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Look closely wt this code. Look at your braces. should be:
| Code: | if (blockEnterButton == 1)
printf(lcd_putc,"\f NO PRESS");
else
printf(lcd_putc,"\f FREE PRESS");
// do something |
or
| Code: | if (blockEnterButton == 1)
{
printf(lcd_putc,"\f NO PRESS");
}
else
{
printf(lcd_putc,"\f FREE PRESS");
// do something
} |
braces are only needed when you have more than 1 line of code inside the statement. |
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DragonPIC
Joined: 11 Nov 2003
Posts: 118
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| Posted: Fri May 13, 2005 12:10 pm |
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And what is the break for?
_________________
-Matt |
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Jurgens
Guest
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| Posted: Fri May 13, 2005 12:33 pm |
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Yes, there is no need for break... and i have correct my errors,
but i still end in "free press" part ??
Jurgens S. |
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Humberto
Joined: 08 Sep 2003
Posts: 1215
Location: Buenos Aires, La Reina del Plata
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| Posted: Fri May 13, 2005 12:53 pm |
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Jurgens wrote:
| Quote: |
but i still end in "free press" part ??
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I donīt see in your code how do you quit a detect condition, you coded:
| Code: |
if (hour < 5)
{
blockEnterTime=1;
}
.........................
if(blockEnterTime == 1)
{
printf(lcd_putc,"Block");
delay_ms(1000);
blockEnterButton=1;
}
.......................
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But I donīt see how/where you clear that condition
| Code: |
blockEnterTime=0;
blockEnterButton=0;
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99.99 of times the testing behaviour is according to the code that we wrote !!! 
Best wishes,
Humberto |
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Jurgens
Guest
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| Posted: Sat May 14, 2005 6:58 am |
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The values are set but i think that something else could be problem.
Wenn i program the chip you get this situation:
First run:
blockButton --> 0 / Free press / do something
Second run:
blockButton --> 0 / No press / Free press / do something
It looks like, like he dose not stop on no press part.
Do i have to make some function for exit (wenn he reach the no press part)? The program should just block the enter press until 5 hours nothing else..
One other thing:
Im timer0 i have 4 if schleifen ( if for sec, min, hours and for 5 hours).
What is wiht timer? Weil i have to count till AND over 5 hours ( till i reach 10 hours ), what happens wenn i set blockTime=0;. Will the timer be reseted or not ? |
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Humberto
Joined: 08 Sep 2003
Posts: 1215
Location: Buenos Aires, La Reina del Plata
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| Posted: Sat May 14, 2005 9:29 am |
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Jurgens,
What you told us is out of our scope and understanding.
| Quote: |
First run:
blockButton --> 0 / Free press / do something
Second run:
blockButton --> 0 / No press / Free press / do something
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Without full C code we canīt help you nor know what/how are you trying to do it.
Humberto |
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Jurgens
Guest
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| Posted: Sat May 14, 2005 11:16 am |
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Second run:
blockButton --> 1 / No press / Free press / do something
Everything is OK accept he dont makes stop on NO PRESS.
| Code: |
...
#define INTS_PER_SECOND 76
int8 sekunden=0, minuten=60, stunden, stunden_sleep=0;
int8 int_count , blockEnterTime, blockEnterButton=0;
#int_rtcc
void clock_isr() {
if(--int_count==0)
{
++sekunden;
int_count = INTS_PER_SECOND;
if(sekunden==60){
minuten++;
}
if(minuten==60){
stunden_sleep++;
stunden++;
}
if(stunden_sleep < 5)
{
blockEnterTime=1;
}
}
}
main()
{
int_count=INTS_PER_SECOND;
set_rtcc(0);
setup_counters (RTCC_INTERNAL, RTCC_DIV_256);
enable_interrupts (INT_RTCC);
enable_interrupts(GLOBAL);
lcd_init();
if (enter_gedruckt == istGedruckt)
{
if(blockEnterTime == 1)
{
printf(lcd_putc,"Block");
delay_ms(1000);
blockEnterButton=1;
}
blockEnterTime=0;
if (blockEnterButton == 1)
{
printf(lcd_putc,"\f NO PRESS");
}
else
{
printf(lcd_putc,"\f FREE PRESS");
delay_ms(2000);
// Enter 4 nummer
printf(lcd_putc,"\f Bitte geben Sie Ihr Nummer ein!");
...
}
} // Enter Taste gedruckt
} // main |
Jurgens |
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Guest
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| Posted: Mon May 16, 2005 1:18 pm |
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| don't you need a loop in your program somewhere? |
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