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sqrt() - can i use a non-float?

 
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valemike
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sqrt() - can i use a non-float?
PostPosted: Tue Dec 21, 2004 8:18 am     Reply with quote
It says in the manual that sqrt() takes in a float and outputs a float. however i found that i can use non-floats, e.g. int32.

Code:

void main(void)
{
    int32 serial_number;
    int32 square_root;
   
    serial_number = 999999;   
    printf ("serial_number = %ld\r\n", serial_number);
    square_root = sqrt(serial_number);
    printf ("square root = %ld\r\n", square_root);
}


The output is:
Code:

serial_number = 999999
square root = 999


Can I thus safely use sqrt() with ints and longs and int32? Or will it be unpredictable with other numbers?

Thanks,
MIke
mvaraujo (not logged)
Guest
PostPosted: Tue Dec 21, 2004 8:51 am     Reply with quote
You can use it with any type of number.

Take care that for integers there are options for sqrt() routine that can be faster (see Code Library on the forum)!

Marcus
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