CCS C Software and Maintenance Offers
FAQFAQ   FAQForum Help   FAQOfficial CCS Support   SearchSearch  RegisterRegister 

ProfileProfile   Log in to check your private messagesLog in to check your private messages   Log inLog in 

CCS does not monitor this forum on a regular basis.

Please do not post bug reports on this forum. Send them to CCS Technical Support

Using PIC as a switch

 
Post new topic   Reply to topic    CCS Forum Index -> General CCS C Discussion
View previous topic :: View next topic  
Author Message
Stanley



Joined: 09 Jan 2004
Posts: 4

View user's profile Send private message

Using PIC as a switch
PostPosted: Sun Apr 25, 2004 1:25 pm     Reply with quote

Hi.

I have 2 AA battery 1.2V 1800mAh Ni-MH connected in serial giving me 2.4V. They are supplying a motor using 800mA and I am going to use a PIC to turn it on and off. I cant loose any voltage over the switch so I was thinking of using a relay or does anyone have a better solution? Is it possible to use some other componets than the relay? If not then does anyone know about a suitable relay to use?

Stanley
Ttelmah
Guest







Re: Using PIC as a switch
PostPosted: Sun Apr 25, 2004 2:21 pm     Reply with quote

Stanley wrote:
Hi.

I have 2 AA battery 1.2V 1800mAh Ni-MH connected in serial giving me 2.4V. They are supplying a motor using 800mA and I am going to use a PIC to turn it on and off. I cant loose any voltage over the switch so I was thinking of using a relay or does anyone have a better solution? Is it possible to use some other componets than the relay? If not then does anyone know about a suitable relay to use?

Stanley


You are going to loose _some_ voltage in any switch. Even a relay has resistance. The 'downside' of a relay, is that the coil will draw significant current (you will need a driver transistor), and there will be a lot of back-emf when the coil is switched off. You will also need to protect the contacts from arcing when the load is switched. The big problem you will have is that this will need to be a relatively special 'low voltage' relay. The first alternative to a relay, is a power MOSFET, but your low voltage will then mean you have to use a seperate circuit to generate the gate drive. The 'on' resistance of a power MOSFET, can be tiny (these are what are being used to control motors drawing thousands of amps now...). The second alternative, is an 'all in one' solution, the 'solid state relay'. These comprise the FET, protections circuitry, and the drive system, built into a single module (for DC versions - the AC versions use triacs, or thyristors). Unfortunately all require that there is enough voltage to drive the input side of an optocoupler, and your supply is 'borderline'. Have a look at the Crydom website, to get an idea of what these modules can do. Most need about 3v.
Tyco, used to do some specialist low voltage relays, but most need at least 3.5v.
Your 'best bet', will probably be to use a charge pump, to give a few mA, at 5v, which will then allow a much larger choice of switching system.

Best Wishes
Rob
Guest







PostPosted: Sun Apr 25, 2004 3:16 pm     Reply with quote

If you're not tied down to having only two batteries you could use four (giving you 4.8 V) and then pulse width modulate through a FET or H-Bridge or most any other power switching technology. You could then use these battereis to power your PIC too. just a thought.
-Rob
Guest 999
Guest







PostPosted: Mon Apr 26, 2004 12:49 am     Reply with quote

Use a latching relay
edi



Joined: 22 Dec 2003
Posts: 82

View user's profile Send private message

PostPosted: Mon Apr 26, 2004 4:32 am     Reply with quote

You can use a new technologic MOSFET that need very low Vgs and has a Rdson of ~100mohm.
If you need 800mA to your load, you will lose ~80mV from the 2.4V source.
One MOSFET for example can be the Fairchild FDN340P (http://www.fairchildsemi.com/pf/FD%2FFDN340P.html)

Good luck
Ttelmah
Guest







PostPosted: Mon Apr 26, 2004 2:47 pm     Reply with quote

edi wrote:
You can use a new technologic MOSFET that need very low Vgs and has a Rdson of ~100mohm.
If you need 800mA to your load, you will lose ~80mV from the 2.4V source.
One MOSFET for example can be the Fairchild FDN340P (http://www.fairchildsemi.com/pf/FD%2FFDN340P.html)

Good luck

It'll perform slightly worse than this. The Rds, gets higher with lower gate drive. At 2.4v, it'll be nearer to 150mohm (and you should really assume that the drive will be a little below the rail). Still great, and well worth considering.

Best Wishes
Stanley



Joined: 09 Jan 2004
Posts: 4

View user's profile Send private message

RE: Using PIC as a switch
PostPosted: Tue Apr 27, 2004 1:56 am     Reply with quote

Thanks for all the help. I think I am going to try the new teck. MOSFET. hope it'l work Smile

Tnx. you'r the best Smile

Stanley
Very Happy
edi



Joined: 22 Dec 2003
Posts: 82

View user's profile Send private message

PostPosted: Wed Apr 28, 2004 9:27 am     Reply with quote

The best FET option I found is the Si6475DQ from Vishay.
It's only 17mOhm at Vgs=-1.8V.
So at 800mA LOAD you lose only 13.6mV.
Display posts from previous:   
Post new topic   Reply to topic    CCS Forum Index -> General CCS C Discussion All times are GMT - 6 Hours
Page 1 of 1

 
Jump to:  
You cannot post new topics in this forum
You cannot reply to topics in this forum
You cannot edit your posts in this forum
You cannot delete your posts in this forum
You cannot vote in polls in this forum


Powered by phpBB © 2001, 2005 phpBB Group