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MCUprogrammer
Joined: 08 Sep 2020
Posts: 221
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| SSD1306 |
 Posted: Sat Apr 06, 2024 6:30 am |
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Hello.
PIC18F26Q71
CCS 5.117
There are 2 logos. I want to print the logo I want. If I try to print one by one, there is no problem. But if I want to choose which logo to print in the function, the whole screen is filled with white pixels.
Where am I going wrong?
Let me share the relevant parts of the code.
| Code: |
rom uint8_t Logo1[64][16] = {................} // There's hex data inside.
rom uint8_t Logo2[96][12] = {................} // There's hex data inside.
Function prototype
void pDisplay(uint8_t startX, uint8_t startY, uint8_t width, uint8_t height,uint8_t *printLogo);
The function I sent.
pDisplay(0, 0, 128,64,Logo1);
void pDisplay(uint8_t startX, uint8_t startY, uint8_t width, uint8_t height,uint8_t *printLogo)
{
uint8_t x, y;
uint8_t displayX, displayY;
uint8_t value, i;
uint8_t screenWidth = 128;
uint8_t screenHeight = 64;
// Exit the function if the image exceeds the screen size
if (startX + width > screenWidth || startY + height > screenHeight)
{
return;
}
displayY = startY;
for(y=0;y<height;y++)
{
displayX = startX;
for(x=0;x<width;x++)
{
if((x % 8) == 0)
{
value = printLogo[(height - 1) - y][x/8];
i = 7;
}
oled_pixel(displayX, displayY, bit_test(value, i) == 0);
displayX++;
i--;
}
displayY++;
}
}
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Best Regards...
MCUprogrammer
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temtronic
Joined: 01 Jul 2010
Posts: 9232
Location: Greensville,Ontario
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| Posted: Sat Apr 06, 2024 6:45 am |
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what you give isn't a program to chose which of the 'logos' to print.
assuming that each 'logo' does display properly, it's not the 'display' function problem. |
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MCUprogrammer
Joined: 08 Sep 2020
Posts: 221
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| Posted: Sat Apr 06, 2024 6:51 am |
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I don't understand what you mean.
_________________
Best Regards...
MCUprogrammer
_______________________________
Work Hard |
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gaugeguy
Joined: 05 Apr 2011
Posts: 303
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| Posted: Mon Apr 08, 2024 7:50 am |
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When you pass the address of a pointer, you are only passing the start address.
It does not have any inherent knowledge of whether it is a multi-dimensional array. You will need to treat it as a one-dimensional array and calculate the location based on the size of the array. |
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