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shift_right help please

 
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Kasper



Joined: 14 Jan 2004
Posts: 88
Location: Aurora, Ontario, Canada

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shift_right help please
PostPosted: Tue Jan 20, 2004 1:45 pm     Reply with quote
Hi.
in trying to implement the below code, the compiler keeps giving me an error:
*** Error 28 "..." Line 86(32,45): Expecting an identifier

looking at the manual, I cannot really tell what I am doing wrong here :(
Any help would be appreciated
Compiler: 3.184, WinXP, 16F877, ICD2

This is what it says in the manual:
Quote:

// This shifts 8 bits out PIN_A0, LSB first.
for(i=0;i<8;++i)
output_bit(PIN_A0,shift_right(&data,1,0));



Code:


#define ReceiveBufferSize 25

char ReceiveBuffer[ReceiveBufferSize];
main() {
for(i=0;i<(8*ReceiveBuffer);i++) {
   output_bit(pin_a0,shift_right(&ReceiveBuffer,1,0));
   output_high(S2);
   delay_us(TCLKH);   
   output_low(S2);
   delay_us(TCLKL);   
   }// end of for.

}// end main
[/quote]
PCM programmer



Joined: 06 Sep 2003
Posts: 21708

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PostPosted: Tue Jan 20, 2004 5:40 pm     Reply with quote
The problem is in this line:
Quote:
output_bit(pin_a0,shift_right(&ReceiveBuffer,1,0));

ReceiveBuffer is an array, and in C, the name of the array, used by
itself, is the address of the 1st element. You don't need the & symbol.
That's why the compiler is complaining.

Another way to get the address of the 1st element is this:
&ReceiveBuffer[0]

I do have one question. Your ReceiveBuffer array has 25 elements,
but you have set the middle number in the shift_right() function = 1.
This will cause it to only shift the first array element. Based on
the rest of your code, I think you really want to set it = 25.

ie., the corrected line should look like this:
output_bit(PIN_A0, shift_right(ReceiveBuffer, RECEIVE_BUFFER_SIZE,0));
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