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Assign an array value to variable

 
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aaronik19



Joined: 25 Apr 2011
Posts: 297

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Assign an array value to variable
PostPosted: Thu Jul 10, 2014 10:42 pm     Reply with quote
Dear all,

I have an array such as

Code:
varia[2] ={5,45}


Now i have another variable
Code:
int8 knife
and i want to assigned the value of array
Code:
varia[1]
by make the following statement but for some reason it is not working. The variable is remaining as 0

Code:
int8 knife = varia[1];


Can someone tell me what i am making wrong, maybe i am missing something.
PCM programmer



Joined: 06 Sep 2003
Posts: 21708

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PostPosted: Thu Jul 10, 2014 11:42 pm     Reply with quote
Just do it like this and then it will work:
Code:
void main()
{
int8 varia[2] ={5,45};
int8 knife;

knife = varia[1];


while(1);
}
alan



Joined: 12 Nov 2012
Posts: 357
Location: South Africa

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PostPosted: Thu Jul 10, 2014 11:42 pm     Reply with quote
At compile time the comlier only works with literals, knows nothing about what are in "PIC memory".

Why not use a #define VAL 45
then varia[2]= {5, VAL}
int8 knife=VAL

Regards
aaronik19



Joined: 25 Apr 2011
Posts: 297

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PostPosted: Fri Jul 11, 2014 5:14 pm     Reply with quote
Thanks PCM and Alan for your kind help. Everything worked fine now. Just to let you know that the first time I forgot to put the the routine in function. But now it ok.

To make the second step, I am creating two arrays such below. I am right if i say that if I create two-dimensional array I can increment the first coordinate [i] to load the second array in the memory?

Code:
int8 alarm[1][7] = {11,7,14,4,0,6,05};
int8 alarm[2][7] = {11,7,14,4,0,8,05};


Thanks
PCM programmer



Joined: 06 Sep 2003
Posts: 21708

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PostPosted: Fri Jul 11, 2014 5:22 pm     Reply with quote
No, you don't initialize a 2-dimensional array like that. Do it like this:
Code:

int8 alarm[2][7] = {
{11,7,14,4,0,6,05},
{11,7,14,4,0,8,05},
};
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