Alais naming method.

[Neutone]

How do I locate a byte indirectly? I know their has to be some simple way to make this work.

int8 PacketBuffer[24],slave;
#locate slave = *PacketBuffer[0]

This does not work.
I want to make an alais name for the first array location of of an array.
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This message was ported from CCS's old forum
Original Post ID: 11685

[Tomi]

Do you want to locate a byte directly or do you want to create an alias ? Making alias in C means a #define directive:
#define slave PacketBuffer[0]

Example:
PacketBuffer 000000C9 // from list file

0000 00542 .................... slave = 0x10;
0078 3010 00543 MOVLW 10
0079 1683 00544 BSF 03.5
007A 00C9 00545 MOVWF 49 // 0x80+0x49=0xC9 !




:=How do I locate a byte indirectly? I know their has to be some simple way to make this work.
:=
:=int8 PacketBuffer[24],slave;
:=#locate slave = *PacketBuffer[0]
:=
:=This does not work.
:=I want to make an alais name for the first array location of of an array.
___________________________
This message was ported from CCS's old forum
Original Post ID: 11688

[R.J.Hamlett]

:=How do I locate a byte indirectly? I know their has to be some simple way to make this work.
:=
:=int8 PacketBuffer[24],slave;
:=#locate slave = *PacketBuffer[0]
:=
:=This does not work.
:=I want to make an alais name for the first array location of of an array.

Don't bother to try to force a declaration like this (they only accept constants, and your syntax would be wrong anyway - you require the address, not the contents of a pointer). Instead just use the macro language. So:

#define slave (PacketBuffer[0])

Will give a 'psuedonym' for the first entry, and the compiler (since it uses a constant address), will replace this with a direct access, with no array overhead.

Best Wishes
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This message was ported from CCS's old forum
Original Post ID: 11699