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I need help in coding

 
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olivier



Joined: 08 Apr 2010
Posts: 11

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I need help in coding
PostPosted: Fri May 27, 2011 8:04 am     Reply with quote

Hi everyone,
I am new in C programming and I need help in find out what wrong.

I have global variable executed_time and its updated after the function call, then printf. For some reason it keep printing zero. I try to find where I init it to zero but don't know where it come from.

here is my code
Code:

char Seconds = 0,Interrupt_Flag = 0, interruption_time = 0;
float executed_time = 0.00000;
int32 Inst_Cycle_Per_Second = 0;

void my_time_ms (char i,j,k);
void LCD_Pwr_Initialze(void);
void Power_On_Chk (void);
void RTC_Initialize (void);
void Final_Delay_Time (void);
void Blink_LED (char number_flash, int flash_duty_cycle);

void main()
{
   RTC_Initialize();
   while (TRUE)
   {
      Seconds = 0;                // clear all global variables before next test             
      Interrupt_Flag = 0;
      interruption_time = 0;
      executed_time = 0.00000;
      Inst_Cycle_Per_Second = 0;
      i = 1;
      while (input(START_SW) == 1)
      {
         if (i == 1)
         {
            lcd_gotoxy (7,2);   
            printf (lcd_putc, "READY !");      //do nothing
              i = 0;   
         }
      }
      clear_interrupt(int_timer1);
      set_timer1(0);
      clear_interrupt(INT_EXT);
      enable_interrupts(GLOBAL);
      do
      {
        ;
      } while ((input (STOP_SW) == 1) && (interrupt_flag == 0));
      executed_time = Final_Delay_Time();
      printf (lcd_putc,"%7.5f S",executed_time);   
      while (input(RESET_SW) == 1)
      {
         ;//do nothing and wait for reset switch pressed to start new test
      }
      printf (lcd_putc, "\f");   //clear lcd screen
   } //end of main while loop
}//end of main

Final_Delay_Time ()
{
   float delay_time = 0.00000;
   executed_time = INTERNAL_FREQUENCY - Inst_Cycle_Per_Second - get_timer1();   
   executed_time = executed_time * (1/INTERNAL_FREQUENCY);
   delay_time = Seconds + executed_time;                                 
   return (delay_time);
}
gpsmikey



Joined: 16 Nov 2010
Posts: 588
Location: Kirkland, WA

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PostPosted: Fri May 27, 2011 8:23 am     Reply with quote

Well, one obvious thing that I see is your line:
Code:
executed_time = executed_time * (1/INTERNAL_FREQUENCY);

if "executed_time" starts as 0, then anything times 0 is still 0 --- perhaps you meant to ADD the increment, not multiply ?

mikey
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mikey
-- you can't have too many gadgets or too much disk space !
old engineering saying: 1+1 = 3 for sufficiently large values of 1 or small values of 3
olivier



Joined: 08 Apr 2010
Posts: 11

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PostPosted: Fri May 27, 2011 9:28 am     Reply with quote

gpsmikey wrote:
Well, one obvious thing that I see is your line:
Code:
executed_time = executed_time * (1/INTERNAL_FREQUENCY);

if "executed_time" starts as 0, then anything times 0 is still 0 --- perhaps you meant to ADD the increment, not multiply ?

mikey


Mikey,
thank you for replying back.
I have executed_time = 0; as the begining then
"executed_time = INTERNAL_FREQUENCY - Inst_Cycle_Per_Second - get_timer1();
"
this line should give it a different number. then "executed_time = executed_time * (1/INTERNAL_FREQUENCY); "
should not be zero.
andrewg



Joined: 17 Aug 2005
Posts: 316
Location: Perth, Western Australia

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PostPosted: Fri May 27, 2011 10:06 pm     Reply with quote

I don't know what INTERNAL_FREQUENCY is (please include all your code), but if it's an integer (and I suspect it is), then
Code:
(1/(anything greater than 1))
will be calculated by the compiler as zero due to integer math and rounding down. Then you have:
Code:
executed_time = executed_time * 0;
which is, of course, zero! Perhaps
Code:
executed_time = executed_time / INTERNAL_FREQUENCY;
will work better?
_________________
Andrew
Wayne_



Joined: 10 Oct 2007
Posts: 681

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PostPosted: Thu Jun 02, 2011 3:56 am     Reply with quote

I biggest error I can see is that your function Final_Delay_Time () definition does not include a return type!

Not sure how the compiler would handle that.

float Final_Delay_Time () ?????????
gpsmikey



Joined: 16 Nov 2010
Posts: 588
Location: Kirkland, WA

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PostPosted: Thu Jun 02, 2011 4:04 am     Reply with quote

Hmmm - I missed that one - I would think the compiler *should* at least warn you about a mismatch between the prototype and the actual function.

mikey
_________________
mikey
-- you can't have too many gadgets or too much disk space !
old engineering saying: 1+1 = 3 for sufficiently large values of 1 or small values of 3
olivier



Joined: 08 Apr 2010
Posts: 11

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PostPosted: Fri Jun 03, 2011 10:59 am     Reply with quote

gpsmikey wrote:
Hmmm - I missed that one - I would think the compiler *should* at least warn you about a mismatch between the prototype and the actual function.

mikey

the compiler told me that I can not use void so I remove void
Code:

void Final_Delay_Time (void)
{...;}


to Final_Delay_Time ()
and after that the compiler does not say a thing.

I will change that to float Final_Delay_Time() then.

if I am not return anything do I still need to define float or integer for function?
thank you for help.

as far as my execute_time always zero concern, I define INTERNAL FREQUENCY on top of my code as
Code:

#define XTAL_FREQUENCY  8000000
#define INTERNAL_FREQUENCY  (1/XTAL_FREQUENCY)

when I debug my code with whole bunches of printf to RS232, I found that INTERNAL_FREQUENCY somehow change. the result is random each time the code execute at the main function. I then do this
Code:

#define XTAL_FREQUENCY 800000

float INTERNAL_FREQUENCY = 0;

void main ()
{
INTERNAL_FREQUENCY = 1/XTAL_FREQUENCY;
...
...
..
}

that fix my problem. I still new and as of this point, I just add a band aid on top of my problem. I will revisit the problem again to find out why later on.
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