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Weird result with read and write float to EEPROM

 
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janater123



Joined: 10 Dec 2010
Posts: 1

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Weird result with read and write float to EEPROM
PostPosted: Fri Dec 10, 2010 6:45 am     Reply with quote

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Locked.
Reason: Atmega328p, AVR GCC are off-topic for CCS

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I've really bashed my head around trying to figure out why the following code doesn't work. I am trying to write float values to the EEPROM of Atmega328p, using AVR GCC.

The output is "?" to the screen when I expect "14.4". Can someone verify that this does/doesn't work for them, or if the solution is obvious?

By the way, I included a write to the EEPROM with an integer value just to show that writing to the EEPROM is working correctly. The value "55" is printed to the screen.
code:


Code:

int main(void)
{
   init();

     float set_value_float;
     float read_value_float;
     int set_value_int;
     int read_value_int;

   printf("starting up");

     set_value_float = 14.4;
     set_value_int = 55;
      
     write_to_EEPROM( EEP_INT_LOCATION, set_value_int );
    write_float_eep( EEP_FLOAT_LOCATION, set_value_float );

     read_value_int = read_from_EEPROM( EEP_INT_LOCATION );
     read_value_float = read_float_eep( EEP_FLOAT_LOCATION ); 
    printf( "\r\nRead float value: %.1f\r\nRead int value: %u",read_value_float, read_value_int );
     
    while(1){}
}

//EEPROM
void write_float_eep(unsigned int address, float data) {

   
   write_to_EEPROM(address,*((char*)&data));
   write_to_EEPROM(address+1,*((char*)&data+1));
   write_to_EEPROM(address+2,*((char*)&data+2));
   write_to_EEPROM(address+3,*((char*)&data+3));

}

float read_float_eep(unsigned int address) {
    float temp;
    *((char*)&temp) = read_from_EEPROM(address);
    *((char*)&temp+1) = read_from_EEPROM(address+1);
   *((char*)&temp+2) = read_from_EEPROM(address+2);
    *((char*)&temp+3) = read_from_EEPROM(address+3);
         
    return (temp);       

}
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