How store values hexdecimal in a variable

[pilar]

Hi, I need to store the following values hexdecimal in a variable , someone could tell me how?

These are the Values:

[Ttelmah]

Don't...
The chip works in binary. Hexadecimal, is just a way of representing numbers.
You can put values into an array in any number format you want, but they'll be stored as binary internally. Constant declarations support binary, decimal, octal, and hex input.
Then simply convert your incoming text to binary as well, and compare.

You can put constant values into an array, with a mix of formats. So:

[Douglas Kennedy]

Your question probably needs to be more specific.
Hexadecimal is notation for integers in base 16. To the pic everything is internally notated in binary. Now humans like alphabets so we use characters 0..9 abcdef to notate hexadecimal. Suppose the transmission to your uart uses this alphabetic notation and that the characters are themselves encoded using ascii then you have choices to make.
You could store the values internally in the PIC into a character array in which two characters store the ascii value of the alphabetic hexadecimal notation. Ex the character 3 ascii (51 in base 10). This choice involves always checking 2 char for comparisons. Alternatively you could convert the two ascii chars as follows and renotate the value as int 8.
int8 high nibble=(ascii val High nibble char-48) when 0...9
and (ascii val High nibble char-96)+9 when a....f
int8 low nibble=(ascii val low nibble char-48) when 0...9
and (ascii val low nibble char-96)+9 when a....f

int8 test var=(high bibble)*16+(low nibble)
Now if you define your constant hexadecimal table to the compiler using an array of int8 and syntax 0x00.......0x0f the compiler will notate this array internally as binary.
CCS has examples of hex conversion with functions like get_hex that will perform the pseudo code above.

[pilar]

Thank you..