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output_high() in a "for(;;)" cycle

 
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cmussoni



Joined: 21 Aug 2010
Posts: 7

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output_high() in a "for(;;)" cycle
PostPosted: Sat Aug 21, 2010 8:02 am     Reply with quote

Hello to all,
I've this stupid doubt. In this code:
Code:

void main(){
   ...
   set_tris_c(0b00000000);
   ...
   for(;;){
      delay_ms(1000);
      output_high(PIN_C0);
      delay_ms(1000);
   }
}

PIN_C0 is blinking with a 1 second rate. Why?
Why in this for-cycle the PIN_C0 turns off?
(I don't write "output_low(PIN_C0)" )
Thanks a lot to all.
Claudio
FvM



Joined: 27 Aug 2008
Posts: 2337
Location: Germany

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PostPosted: Sat Aug 21, 2010 8:21 am     Reply with quote

May be a case of the well-known RMW problem. Increase the load resistor connected to the output to achieve a legal logic "1" level at the pin.

Or did you enable the watchdog timer?
cmussoni



Joined: 21 Aug 2010
Posts: 7

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output_high() in a "for(;;)" cicle
PostPosted: Sat Aug 21, 2010 10:25 am     Reply with quote

Hello,
I've no WDog (#fuses XT, NOWDT...). I don't try to change the output load but when I bring out the code :
Code:

delay_ms(1000);
output_high(PIN_C0);
delay_ms(1000);

from the infinite loop for(;;) the output blinks no more.
Any other idea ?
Thanks a lot
Claudio
cmussoni



Joined: 21 Aug 2010
Posts: 7

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output_high() in a "for(;;)" cicle
PostPosted: Sat Aug 21, 2010 10:28 am     Reply with quote

...ooops... I remind I' m working with a PIC16F876A.
Bye.
dyeatman



Joined: 06 Sep 2003
Posts: 1934
Location: Norman, OK

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PostPosted: Sat Aug 21, 2010 10:52 am     Reply with quote

Why don't you post the entire (compilable) program so we can test it rather than play guessing games?
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cmussoni



Joined: 21 Aug 2010
Posts: 7

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PostPosted: Sat Aug 21, 2010 11:08 am     Reply with quote

Ok there it is :
Code:

#include <16F876A.h>

#fuses   XT, NOWDT, NOPROTECT, NOPUT, NOBROWNOUT, NOLVP
#use delay (clock=4000000)

#define  TX232 PIN_A2
#define  RX232 PIN_A5

#define  INTSP PIN_A4

#use rs232(baud=9600, xmit=TX232, rcv=RX232)

BYTE int_count;

#define INTS_PER_2_SECOND 20   
#INT_TIMER0

int FLAGOK=0;
int timeout=0;
int DATOIN=0;
int current_b=0;
int current_c=0;

void  READDATA(){
   FLAGOK=0;
   delay_us(100);
   timeout=0;
   while(!kbhit() && (++timeout<5000)){   // 0,05 second
   delay_us(10);
   }

   if(kbhit()){
      DATOIN=getc();
      FLAGOK=1;
   }
   else {
      FLAGOK=0;
   }
}

void main(){

   set_tris_a(0b00110010);
   set_tris_b(0b11111111);
   set_tris_c(0b00000000);

   port_b_pullups(TRUE);
   delay_ms(100);

   for(;;){
      READDATA();
      delay_ms(200);
      output_high(PIN_C0);
      delay_ms(1000);
    }
}
FvM



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Posts: 2337
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PostPosted: Sat Aug 21, 2010 11:19 am     Reply with quote

And the CCS version, please.
cmussoni



Joined: 21 Aug 2010
Posts: 7

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PostPosted: Sat Aug 21, 2010 11:41 am     Reply with quote

IDE 4.093
PCB 4.093
PCM 4.093
PCH 4.093
PCD 4.093
Cool
cmussoni



Joined: 21 Aug 2010
Posts: 7

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PostPosted: Sat Aug 21, 2010 11:52 am     Reply with quote

Sorry, sorry. The complete for-cycle is the sequence:
Code:

for(;;){
      current_b=input_b();
      delay_us(100);
      current_c=input_c();
      delay_us(100);

      READDATO();
      delay_ms(200);
      output_high(PIN_C0);
      delay_ms(1000);
}
FvM



Joined: 27 Aug 2008
Posts: 2337
Location: Germany

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PostPosted: Sat Aug 21, 2010 1:17 pm     Reply with quote

Quote:
Sorry, sorry. The complete for-cycle is the sequence:

O.K. input_c() sets all port c pins to tri-state, because default #USE STANDARD_IO is in effect.
Ttelmah



Joined: 11 Mar 2010
Posts: 19513

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PostPosted: Sat Aug 21, 2010 2:57 pm     Reply with quote

OK.
Several problems.
You have a #int declaration, without interrupt handler code after it. Either get rid of this declaration, or put a handler there...
You have a timeout counter, going to 5000, declared as an integer. An int, in CCS, can hold 255 max. This will never timeout.
This is why you don't get a blink.
Then, if the timeout was working, your delay here will be several instructions more than 10uSec. In fact the time will probably be nearly twice this.
You do realise that using a software UART, you _must_ poll the pin at intervals no longer than 0.5 a bit time. Any data that arrives in the 1200mSec comprising the rest of your loop, _will_ be lost. The actual 'odds' of seeing a serial character, are extremely poor indeed.

Best Wishes
cmussoni



Joined: 21 Aug 2010
Posts: 7

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PostPosted: Sun Aug 22, 2010 1:26 am     Reply with quote

FvM...THAAANKS for the solutions: input_c() set PORTC to input !!!

Thank also Ttelmah for all the other my oversights. Rolling Eyes

Bye
Claudio
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