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project2010
Joined: 14 Mar 2010
Posts: 21
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| problem of 4x4 keypad |
 Posted: Sun Mar 14, 2010 3:50 am |
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I have built a 4x4 keypad code, using port B0-7 col1=pin_b0.
Anyone can tell me what's the problem? It doesn't work....
| Code: |
#include <18F4620.h>
#fuses HS,NOWDT,NOPROTECT,NOLVP,NODEBUG
#use delay(clock = 20000000)
#use rs232(baud=9600, xmit=PIN_C6, rcv=PIN_C7)
#include <LCD16x2.c>
#byte TRISB= 0xF95
#byte PORTB = 0xF83 //move the port d into address 0xF83
#bit row1 = PORTB.4 //set the row connector to port d bits
#bit row2 = PORTB.5
#bit row3 = PORTB.6
#bit row4 = PORTB.7
int8 key_scan(void);
int8 keypad();
int8 key_scan(void)
{
int8 key_array[17]={1,4,7,12,2,5,8,0,3,6,9,14,10,13,11,15,16}; //set the pattern of keypad
int8 i,key_no=0,temp = 0xFE;
TRISB= 0xF0; //set rows connector to high on software
for (i=0;i<4;i++) //loop four times to check buttons
{
PORTB = temp;
if (row1) key_no++; else goto keyexit;
if (row2) key_no++; else goto keyexit;
if (row3) key_no++; else goto keyexit;
if (row4) key_no++; else goto keyexit;
temp*=2;
temp++;
}
keyexit:
return key_array[key_no]; //export a number
}
int8 keypad()
{
int8 key;
key=key_scan();
if (key==0) printf(lcd_putc,"Y");
if (key==1) printf(lcd_putc,"1");
if (key==2) printf(lcd_putc,"4");
if (key==3) printf(lcd_putc,"7");
if (key==4) printf(lcd_putc,"2");
if (key==5) printf(lcd_putc,"5");
if (key==6) printf(lcd_putc,"8");
if (key==7) printf(lcd_putc,"3");
if (key==8) printf(lcd_putc,"6");
if (key==9) printf(lcd_putc,"9");
if (key==10) printf(lcd_putc,"N");
if (key==11) printf(lcd_putc,"C");
if (key==12) printf(lcd_putc,".");
if (key==13) printf(lcd_putc,"0");
if (key==14) printf(lcd_putc,"/");
if (key==15) printf(lcd_putc,"D");
delay_ms(50);
while (key_scan()!=16); //wait for leave pressing
delay_ms(50);
return key;
}
void main()
{
int8 key;
setup_psp (PSP_DISABLED);
lcd_init();
printf(lcd_putc,"Biometric attendance");
printf(lcd_putc,"Welcome!!");
delay_ms(1000);
lcd_init();
printf(lcd_putc,"1.123456\n");
printf(lcd_putc,"2.abc");
delay_ms(50);
while(true)
{
key=key_scan();
if (key == 1)
{ printf(lcd_putc,"xxxx");
delay_ms(50);
while (key_scan()!=16);
delay_ms(50);
}
if (key == 2)
{ printf(lcd_putc,"yyyy");
delay_ms(50);
while (key_scan()!=16);
delay_ms(50);
}
else
{ printf(lcd_putc,"99999");}
}
}
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my sch., always high??
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FvM
Joined: 27 Aug 2008
Posts: 2337
Location: Germany
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| Posted: Sun Mar 14, 2010 5:50 am |
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How do you determine, that particularly the keypad is "not working"? All debug output goes to the LCD.
Is it a real circuit or a simulation?
Where did you connect the LCD? |
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PCM programmer
Joined: 06 Sep 2003
Posts: 21708
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Ttelmah
Joined: 11 Mar 2010
Posts: 19505
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| Posted: Sun Mar 14, 2010 3:51 pm |
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Though I agreee 'use the existing driver', The reason it doesn't work, is the maths of 'temp'.
You want this to pull each line low in turn.
Ignoring the top nibble, you have 1110 in it at the first loop. At the end of this loop, you multiply it by 2 -> 1101, then increment it -> 1110. Er.....
You only need to multiply it by two to move the '0' left.
Best Wishes |
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