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| Author |
Message |
takumi
Joined: 07 Mar 2009
Posts: 14
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| how to control by bit! |
 Posted: Wed Jan 06, 2010 7:27 pm |
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Hi all, I need some help to understand about controlling output ports by
bit. The code is as follows (PIC16F877A):
| Code: |
#define sensor1 PIN_D0
#define sensor2 PIN_D1
#define motor1 PIN_B0
#define motor2 PIN_B1
void main(){
while (1){
if(input(sensor1)==1 && input(sensor2)==1){
output_b(0b00000011);
}
else if(input(sensor1)==0 && input(sensor2)==1){
output_b(0b00000001);
}
else if(input(sensor1)==1 && input(sensor2)==0){
output_b(0b00000010);
}
else {
output_b(0b00000000);
}
}
} |
The question is instead of using
| Code: | | output_b(0b00000011); |
can I do this:
| Code: | | output_b(0b000000|motor1|motor2); |
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mickey231bhq
Joined: 06 Apr 2005
Posts: 19
Location: Formosa
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| Posted: Wed Jan 06, 2010 7:35 pm |
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| you can use "output_high" and "output_low". |
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SherpaDoug
Joined: 07 Sep 2003
Posts: 1640
Location: Cape Cod Mass USA
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| Posted: Wed Jan 06, 2010 8:21 pm |
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Try this:
| Code: |
#define mot1mask 0b00000001
#define mot2mask 0b00000010
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Then you can turn the motors on and off with this:
| Code: |
output_b(mot1mask|mot2mask); //both motors on
output_b(~mot1mask&~mot2mask); //both motors off
output_b(mot1mask&~mot2mask|mot3mask&~mot4mask); //motors 1&3 on, 2&4 off |
_________________
The search for better is endless. Instead simply find very good and get the job done. |
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