Setting 2 pins high or low simultaneously

[Futterama]

Hi forum,

I'm using the PIC10F222 and would like to set 2 pins high in the same instruction and also set the same 2 pins low in the same instruction.

I guess I need to read the GPIO register and then use the bitwise AND and OR operators and then write the modified values back to the GPIO register.
The problem is that I have completely forgotten how to use bitwise operators.

I got this code:

[Futterama]

Hi,

I found the possibility to test the above code, and it seems to work, but still, I'm not sure the outputs change simultaneously, I don't have the equipment to check.

Anyone?

[SherpaDoug]

Yes, that should work. But the easy way to find out without a scope is to look at the assembly code in the .lst file.
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[Futterama]

[Gabriel]

if you output a byte to a port

all pins in that port will set simultaneously...ethier low or high or combinations.

set port B = 0xFF , all pins go high,

set port B = 0x00 , all pins go low...

set port B = 0x0F , higher half goes low, lower half goes high

and so on...

(this is not actual code... im sure you get what i mean)

hope i helped...if you still needed help at this point...(alot of smart people around here)

gabriel
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CCS PCM 5.078 & CCS PCH 5.093

[bungee-]

With logical OR or AND you are "masking" the port so if you turn it all on or all off it will be simultaneously for whole port. Or in your case for two I/O pins.

Those two instructions in your case d the following thing. First one loads 06 (or 0b00000110) to the W register and the second one executes logical OR on register at location 06 (that is GPIO) and result is saved to the register it self.

Hope the explanation helps.

[Futterama]

Thanks for your replies, but I got it working OK now

bungee, I thought it worked that way, you confirmed it for me, thanks.