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interrupts on 16f628a

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filjoa

Joined: 04 May 2008
Posts: 260

interrupts on 16f628a

Posted: Mon Dec 07, 2009 5:54 pm

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Hi

I try use this PIC with interrupts.

On datasheet it have one external interrupt on pin RB3 and I like use it to connect a switch, but I like connect on other RB pins some leds.

Program work if I make some like this:

My problem stay on use interrupt on pin RB0 and call him to make my sequence.

Code:

int8 count = 0;

#int_ext
void int_rb0()
{
count++:
}

void seq1()
{
Output_B(0b01000000);
Output_B(0b00100000);
Output_B(0b00010000);
Output_B(0b01000000);
Output_B(0b00100000);
Output_B(0b00010000);
}

void seq2()
{
Output_B(0b00000000);
Output_B(0b01000000);
Output_B(0b01100000);
Output_B(0b01110000);
Output_B(0b01111000);
Output_B(0b01110000);
Output_B(0b01100000);
Output_B(0b01000000);
}

void main()
{
enable_interrupts(GLOBAL);
enable_interrupts(INT_EXT);
setup_timer_2(T2_DIV_BY_1, 255, 1);
setup_ccp1(CCP_PWM);
set_pwm1_duty(0); //0 até 255

while(1)
{
if (count==0) seq1();
if (count==1) seq2();

if (count>=2) count=0;
}
}

Best regards

filjoa

Joined: 04 May 2008
Posts: 260

Posted: Thu Dec 10, 2009 8:21 am

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Hi

Interrupts finally work fine but have a problem....

When I write this:

Code:

void seq1()
{
Output_B(0b00000001); delay_ms(200);
Output_B(0b00000100); delay_ms(200);
Output_B(0b00000010); delay_ms(200);
Output_B(0b00001000); delay_ms(200);
}

It don't work... I need write this way:

Code:

void seq1()
{
output_high(PIN_B7); output_low(PIN_B6);output_low(PIN_B5); output_low(PIN_B4); delay_ms(200);
output_low(PIN_B7); output_high(PIN_B6);output_low(PIN_B5); output_low(PIN_B4); delay_ms(200);
output_low(PIN_B7); output_low(PIN_B6);output_high(PIN_B5); output_low(PIN_B4); delay_ms(200);
output_low(PIN_B7); output_low(PIN_B6);output_low(PIN_B5); output_high(PIN_B4); delay_ms(200);
}

Someone can explain me why?

PS: It only occur on PIC16F628A because I try on PIC18F252 and this two ways work fine.

best regards

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