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16 bit transfer with rs232

 
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krakatau



Joined: 19 Feb 2009
Posts: 9

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16 bit transfer with rs232
PostPosted: Wed Mar 11, 2009 10:11 am     Reply with quote

hi,
My question is very short.
I want to 16bit transfer with rs232 protocol, is it possible?
What do I do?
I will use to pic16f876 to 16bit shift register.
16bit transfer or 8bit 8bit transfer.

thanks
Guest








PostPosted: Wed Mar 11, 2009 10:54 am     Reply with quote

Hi krakatau, you have to send 8 bits and then another 8 bits. If you want to recieve it in a 16 bits register you have to do something like this:

var=BufferReception;
var=(var<<8)| BufferReception;

your 'var' has the 16bits data you wanted to send. But you have to be careful with the first 8 bits that you send, in this example I send the upper 8bits and then the lower.
Ttelmah
Guest







PostPosted: Wed Mar 11, 2009 11:05 am     Reply with quote

Remember also, that with RS232, there are start and stop bits each side of the data. To transfer directly to a shift register, you'd really want to be using SSP, then a clock is provided as well, and if you implement slave select, this can reset the shift register. Again 8 bit transfers, but you simply operate the select line, and send two transfers, which will include the clocks to operate the register.

Best Wishes
krakatau



Joined: 19 Feb 2009
Posts: 9

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PostPosted: Thu Mar 12, 2009 1:26 am     Reply with quote

first of all thanks your quickly replies.. i suppose rs232 can't 16bit transfer directly.it s true? i worked that ;
16bit data, from PC to pic16f876 to another pic16f876 and then this 16bit data will send to 16bit shift register. so 16f876-16f876-shiftregister-on the shiftregister_output.
yesterday i wrote like above code;
for master;

Code:
#use rs232(baud=9600, parity=N, xmit=pin_c6, rcv=pin_c7)
int16 x;
while(1)
{
x=0xffff;
putc(x);
}

for slave;

Code:
#use rs232(baud=9600, parity=N, xmit=pin_c6, rcv=pin_c7)
int16 y;
int z;
while(1)
{
y=getc();
z=make8(y, 1);
output_b(z);
}

i tired 16bit transfer between two pics
it didn't work.
i read your message.
i will send 8bit transfer from pc to pic. and then 8bit to another pic then first 8bit transfer to shift register(Q15....Q8) immediately second 8bit transfer to shiftregister (Q7....Q0)
is it true???
last question;
i'll send clock from any pin (for example pin_b7) true?

already now thanks a lot guys..[/code]
krakatau



Joined: 19 Feb 2009
Posts: 9

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PostPosted: Fri Mar 13, 2009 7:49 am     Reply with quote

have you any idea??
Ttelmah
Guest







PostPosted: Fri Mar 13, 2009 8:55 am     Reply with quote

You have already had a full reply. Look at the first line, of the very first reply, for what you are missing.

Best Wishes
SherpaDoug



Joined: 07 Sep 2003
Posts: 1640
Location: Cape Cod Mass USA

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PostPosted: Fri Mar 13, 2009 9:35 am     Reply with quote

RS232 or any other serial transfer can't send 16 bits at a time. It cant even send 8 bits at a time. Serial transfers send ONE bit at a time. The usual PIC or PC hardware UART does a serial to 8 bit parallel conversion, but a custom software UART could operate with any word width desired.

Look up the CCS functions make8() and make16().
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krakatau



Joined: 19 Feb 2009
Posts: 9

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PostPosted: Fri Mar 13, 2009 10:05 am     Reply with quote

I found my code is wrong because putc() function's back value have to be 8bit. Its a CCS rule. I tried 16bit transfer. I'll send 8bit, 8bit data transfer, I'm forced to.
I'm ok. Thanks a lot.
Ttelmah
Guest







PostPosted: Fri Mar 13, 2009 3:58 pm     Reply with quote

Not a 'CCS Rule'. A rule if you are talking to an interface supporting byte transfers. Same happens in C on the PC, if you are talking to the RS232...

Best Wishes
dyeatman



Joined: 06 Sep 2003
Posts: 1934
Location: Norman, OK

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PostPosted: Fri Mar 13, 2009 4:03 pm     Reply with quote

The UART hardware parallel to serial shift register only supports 8 bits as well.... It has NOTHING to do with CCS.
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