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rs232 and getc

 
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mpardinho



Joined: 16 Jul 2008
Posts: 8
Location: Mexico

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rs232 and getc
PostPosted: Wed Nov 05, 2008 4:57 am     Reply with quote

i can't work 'if"

if ((letra[5] == 'O') && (letra[4] == 'F')){
}................


Code:

#include <18F252.h>

#FUSES HS
#FUSES WDT
#FUSES WDT128
#FUSES NOLVP
#FUSES CPB
#FUSES PROTECT

#use delay(clock = 8000000)
#use rs232(baud = 9600, parity = N, xmit = PIN_C6, rcv = PIN_C7, bits = 8)


#define Led PIN_A0

char letra[7];

//*---------------------------------------------------------------------------*/
void main() {
   set_tris_a( 0b00000000 );
   set_tris_b( 0b01111111 );

   setup_adc_ports(NO_ANALOGS);
   setup_adc(ADC_OFF);
   setup_wdt(WDT_OFF);
   setup_timer_0(RTCC_INTERNAL);
   setup_timer_1(T1_DISABLED);
   setup_timer_2(T2_DISABLED, 0, 1);
   setup_timer_3(T3_DISABLED|T3_DIV_BY_1);
   
   output_high( Led );
   delay_ms( 1000 );
   printf ( "\n\r\START\n\r" );
   output_low( Led );
     
   while (true) {
      letra[6] = getc();
      for (i = 1; i < 6; ++i) letra[i] = letra[i + 1];
     
      if ((letra[5] == 'O') && (letra[4] == 'N') ) && (letra[3] == 'N') ) {
            printf("ON");
      };
      if ((letra[5] == 'O') && (letra[4] == 'F') ) && (letra[3] == 'F') ) {
            printf("OFF");
      };

   };
}


Last edited by mpardinho on Wed Nov 05, 2008 6:01 am; edited 1 time in total
Ttelmah
Guest







PostPosted: Wed Nov 05, 2008 5:32 am     Reply with quote

Of course it won't....
You are writing each character to the location 'letra[6]'. Getc, gets _one_ character.

Best Wishes
mpardinho



Joined: 16 Jul 2008
Posts: 8
Location: Mexico

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PostPosted: Wed Nov 05, 2008 5:37 am     Reply with quote

i put caracter 2 in 1, 3 in 2
for (i = 1; i < 6; ++i) letra[i] = letra[i + 1];

i get 1 caracter in 6 and put i 5

if i test in proteus is 100% code works
tinley



Joined: 09 May 2006
Posts: 67

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PostPosted: Wed Nov 05, 2008 5:40 am     Reply with quote

if ((letra[5] == 'O') && (letra[4] == 'N') ) && (letra[3] == 'N') ) {
printf("ON);
};
if ((letra[5] == 'O') && (letra[4] == 'F') ) && (letra[3] == 'F') ) {
printf("OFF);
};

two many brackets in wrong places! Change to this:

if (letra[5] == 'O' && letra[4] == 'N' && letra[3] == 'N' ) {
printf("ON);
};
if (letra[5] == 'O' && letra[4] == 'F' && letra[3] == 'F' ) {
printf("OFF);
};
tinley



Joined: 09 May 2006
Posts: 67

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PostPosted: Wed Nov 05, 2008 5:43 am     Reply with quote

Oh, and the printf's are wrong too. Missing quotes, change:

printf("OFF);

to this:

printf("OFF");

and the same with ON
mpardinho



Joined: 16 Jul 2008
Posts: 8
Location: Mexico

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PostPosted: Wed Nov 05, 2008 6:03 am     Reply with quote

i change code......i post without "
the problem is in if(

if(letra=='o' ...........

IN PROTEUS WORK
Wayne_



Joined: 10 Oct 2007
Posts: 681

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PostPosted: Wed Nov 05, 2008 6:05 am     Reply with quote

You must be sending "NO" and "FFO" ?

if you send "ON"

"O" ->
letra[6] = "O"

"N"->
letra[5] = letra[6] ('O')
letra[6] = "N"

so your check would be if ((letra[5] == 'O') && (letra[6] == 'N'))

You have extra ; at the end of your if braces aswell. Won't hurt but don't need them!
if (...)
{
} // <-- No ; required
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