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kender
Joined: 09 Aug 2004
Posts: 768
Location: Silicon Valley
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| Function pointer comparison. Bug in v4.071? |
 Posted: Fri Jun 27, 2008 12:01 am |
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Colleagues,
It’s great that v4 supports function pointers. However, it doesn’t seem to support the function pointer comparison at the moment.
| Code: |
typedef int8 (*fp)(int8, int8); // typedef for our function pointer
int8 do_it(int8 ix, int8 iy)
{
return (ix + iy);
}
// more functions that fit the fp typedef
void main()
{
// . . .
fpFoo = &do_it; // initialize the function pointer.
// . . .
if (fpFoo == &do_it) // during compilation, this line generates ERROR 48: Expecting a (
{
// . . .
}
// . . .
}
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- Nick
_________________
Read the label, before opening a can of worms.
Last edited by kender on Fri Jun 27, 2008 12:06 pm; edited 1 time in total |
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Ttelmah
Guest
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| Posted: Fri Jun 27, 2008 2:05 am |
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The function name itself, _is_ the function's address. You don't need the '&' when referring to it.
Use a cast for comparisons. Given that fpFoo, is the address of a function, it expects to receive two variables. So:
| Code: |
typedef int8 (*fp)(int8, int8); // typedef for our function pointer
int8 do_it(int8 ix, int8 iy)
{
return (ix + iy);
}
// more functions that fit the fp typedef
void main()
{
// . . .
fp fpFoo;
fpFoo = do_it; // initialize the function pointer.
// . . .
if ((int16)fpFoo == (int16)do_it)
{
// . . .
}
// . . .
}
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Best Wishes |
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