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How can i use PORTB instead of output_b()

 
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mutevaggil



Joined: 29 May 2008
Posts: 8

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How can i use PORTB instead of output_b()
PostPosted: Tue Jun 10, 2008 6:56 am     Reply with quote

hi,

i want to use PORTB as output directly, i mean, when i write:
PORTB=1; first led of PORTB will ON.

i defined my registers in main.h:

Code:
#include <16F877A.h>

#byte PORTB = 0x06
#byte TRISB = 0x86

#byte OUTPUT = PORTB
#byte OUTPUT_DIR = TRISB


and main.c:


Code:
 
OUTPUT_DIR=0x00;
   
 while(1)
   {
   OUTPUT=0;
   delay_ms(100);
   OUTPUT=1;
   }



it compiles good. but doesnt work in simulation.
Guest








PostPosted: Tue Jun 10, 2008 7:47 am     Reply with quote

Never used the simulator,but if I was testing this on a scope I would have a delay after output=1.

regards
dyeatman



Joined: 06 Sep 2003
Posts: 1933
Location: Norman, OK

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PostPosted: Tue Jun 10, 2008 9:30 am     Reply with quote

You can either use the Output_bit() function or #bit preprocessor directive
from page 90 of the current manual:

Quote:
#BIT

Syntax: #bit id = x.y

Elements: id is a valid C identifier,
x is a constant or a C variable,
y is a constant 0-7.

Purpose: A new C variable (one bit) is created and is placed in memory at byte x and bit
y. This is useful to gain access in C directly to a bit in the processors special
function register map. It may also be used to easily access a bit of a standard
C variable.

Examples: #bit T0IF = 0xb.2
...
T0IF = 0; // Clear Timer 0 interrupt flag


int result;
#bit result_odd = result.0
...
if (result_odd)

Example Files: ex_glint.c
Also See: #byte, #reserve, #locate, #word
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