Question about 18F series (18F252)

[Pete Smith]

Hi all.

I'm thinking of upgrading my compiler to PCH, so I can use 18F parts (specifically 18F252, because it's pin compatible with the 16F876A we use at present - hopefully I can track down some 18LF parts eventually).

I see the 252 has 1536 bytes of RAM.

How is this accessed? In the 16 series, it's limited to 96 bytes per array (due to the register layout). As far as I can tell, looking at the data sheet, the 18F252, the user RAM is from locations 0x0018-0x7fff.

Is this a totally different way of looking at a PIC, rather than having a limited set of registers, actually having RAM as such?

Does this mean I could actually define an array of 1024 bytes, and it all work?

Many thanks,

Pete.
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Original Post ID: 13020

[Tomi]

Yes. For example I have a declaration of:
char MMCPuffer[512];
and it works fine :)

:=Does this mean I could actually define an array of 1024 bytes, and it all work?
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This message was ported from CCS's old forum
Original Post ID: 13039

[Pete Smith]

:=Yes. For example I have a declaration of:
:=char MMCPuffer[512];
:=and it works fine

That's great.

Now all I need to do is scrape up enough to get the compiler - or get work to buy it for me!

Thanks,

Pete.
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This message was ported from CCS's old forum
Original Post ID: 13040