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Message |
Delfinss
Joined: 05 Apr 2022
Posts: 21
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| TIMER0 and ADC with 16F1509 |
 Posted: Thu Apr 28, 2022 1:22 am |
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Hello everyone
ccs c version 5.007
I haven't been able to get the timer0 interrupt working with adc.
I think I have a problem with the timings.
Can you help me where do you need to pay attention?
I know that the chip can only flash the led with the timer0 interrupt.
| Code: |
#include <16f1509.h>
#device ADC = 10 // 0 ile 1023
#include <math.h>
#use delay(internal=4000000)
#fuses INTRC_IO ,NOWDT ,NOPUT ,NOLVP ,NOPROTECT ,NODEBUG ,NOBROWNOUT ,NOWRT
#use fast_io(c)
#use fast_io(a)
#use rs232 (baud=9600, xmit=pin_B7,rcv=pin_B5, parity=N, stop=1)
#int_timer0
int count_NTC;
int sayi=0;
unsigned int onuf_co;
unsigned int avg_NTC,value,sum_NTC,sum_CO,avg_CO;
float R1 = 22000;
float logR2, R2, T;
float c1 = 0.5699030023e-03, c2 = 2.830523628e-04, c3 = -1.761701742e-07;
void timer0_test()
{
set_timer0(60);
//delay_ms(100);
sayi++;
if(sayi==10)
{
sum_NTC=0;
for (count_NTC=0; count_NTC<8; count_NTC++)
{
value=read_adc();
delay_us(100);
sum_NTC=value + sum_NTC;
}
avg_NTC= sum_NTC/=8;
output_high(pin_a2);
// delay_us(20);
}
if(sayi==20)
{
sum_CO=0;
for (count_NTC=0; count_NTC<8; count_NTC++)
{
onuf_co=read_adc();
delay_us(100);
sum_CO=onuf_co + sum_CO;
}
avg_CO= sum_CO/=8;
output_low(pin_a2);
//delay_us(20);
sayi=0;
}
}
void main()
{
setup_timer_1(T1_DISABLED);
setup_timer_2(T2_DISABLED,0,1);
set_tris_c(0b00001111);
set_tris_a(0x00);
output_a(0x00); //red led
output_c(0x00);
setup_adc(adc_clock_div_8);
setup_adc_ports(sAN4 |sAN7, VSS_VDD );
setup_timer_0(T0_INTERNAL | T0_DIV_256);
while (true)
{
//delay_ms(1000);
//======================NTC============================
set_adc_channel(4); //AN4 analog kanal
delay_us(20);
//========================ONUF_CO=======================
set_adc_channel(7);
delay_us(20);
//===================================================
set_timer0(60);
enable_interrupts(INT_TIMER0);
enable_interrupts(GLOBAL);
//==================red lED==========================
if (( avg_CO > 0) || ( avg_CO < 240) ) {
output_low(pin_a5);
delay_us(20);
}
else if (avg_CO > 245){
output_high(pin_a5);
delay_us(20);
}
//==================green LED ==========================
output_toggle(pin_a4);
delay_ms(1000);
//==================Stein Hart for NTC ==========================
R2 = R1 * (1023.0 / (float)avg_NTC - 1.0);
logR2 = log(R2);
T = (1.0 / (c1 + c2*logR2 + c3*logR2*logR2*logR2));
T = T - 273.15;
//==============================================================
//================== printf ==========================
printf ("Temperature:%f ",T);
printf("AVG_CO-ADC= %lu ",avg_CO);
delay_ms(1000);
}
}
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PCM programmer
Joined: 06 Sep 2003
Posts: 21708
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| Posted: Thu Apr 28, 2022 1:47 am |
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| Quote: |
#int_timer0
int count_NTC;
int sayi=0;
unsigned int onuf_co;
unsigned int avg_NTC,value,sum_NTC,sum_CO,avg_CO;
float R1 = 22000;
float logR2, R2, T;
float c1 = 0.5699030023e-03, c2 = 2.830523628e-04, c3 = -1.761701742e-07;
void timer0_test()
{
|
The #int_timer0 line must go above the interrupt function, with
no other lines of code between the two lines. Example:
| Code: | #int_timer0
void timer0_test()
{
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Ttelmah
Joined: 11 Mar 2010
Posts: 19504
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| Posted: Thu Apr 28, 2022 2:19 am |
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There are also rather a lot of other problems.
He loops, changing the ADC channel. After the first pass, the interrupt
will be enabled, so the ADC will be reading different ADC channels on
some calls than others, with no synchronisation between this and the timer
calls. The values won't have any relationship to these selections... 
Now he is also delaying for an enormous time inside the interrupt on the
10th and 20th calls. Why does he delay 100uSec?.
Tacq is only 7.37uSec, so 8uSec would be plenty.
The sum maths is odd:
avg_CO= sum_CO/=8;
That is not the normal syntax for the operation. It seems to be dividing
sum_CO by 8, writing this into sum_CO, and then copying this into
avg_CO. Probably will work, but an unneeded extra operation.
In the main loop, he reads the two average values, but not even one
timer interrupt will have triggered at this point. He set the count to 60, so
the timer interrupt period will be about 50mSec. He does long delays that
would allow things to happen, after having worked on the readings.
However even these are not enough to allow the 20 cycles needed to
fully generate a reading. It will take three seconds for a pass to complete.
So the first couple of times round the loop, given the avg values are
not initialised, the values will probably be overrange.
Then there is a huge problem with maths types. He has adc=10, but
uses an int for the adc value. 10bit does not go into 8bit....
He then sums this 8 times, so potentially 13bits. This doesn't fit by an
even larger margin.
Then the problem with fast_io. The ADC channels are on port A, but
he sets the whole of this port to be digital outputs.
Get rid of fast_io. It is miles safer to use standard_io (the default).
Avoids this sort of error.
I gave up at this point.... |
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temtronic
Joined: 01 Jul 2010
Posts: 9225
Location: Greensville,Ontario
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| Posted: Thu Apr 28, 2022 5:53 am |
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gee..and here I was thinking...
... hmm 'James Bond' version of compiler...
well know to have a few 'bugs'... |
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Delfinss
Joined: 05 Apr 2022
Posts: 21
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| TIMER0 and ADC with 16F1509 |
| Posted: Fri Apr 29, 2022 3:15 am |
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Thank you very much for your valuable suggestions.
I tried to implement your warnings as far as I can understand.
I used Timer1 because I didn't know how to solve the synchronization problem. But now I can't get the adc values.
avg_CO= sum_CO/=8; I used this to smooth the adc value. If you have different suggestions, I'm listening carefully.
| Code: |
#include <16f1509.h>
#device ADC = 10 // 0 ile 1023
#include <math.h>
#use delay(internal=4000000)
#fuses INTRC_IO ,NOWDT ,NOPUT ,NOLVP ,NOPROTECT ,NODEBUG ,NOBROWNOUT ,NOWRT
#use standard_io(c)
#use standard_io(a)
#use rs232 (baud=9600, xmit=pin_B7,rcv=pin_B5, parity=N, stop=1)
int count_NTC;
int sayi=0;
int mayi=0;
unsigned short int onuf_co; //input_co,opamp_co,
unsigned short int avg_NTC,value,sum_NTC,sum_CO,avg_CO;
float R1 = 22000;
float logR2, R2, T;
float c1 = 0.5699030023e-03, c2 = 2.830523628e-04, c3 = -1.761701742e-07;
#int_timer0
void timer0_test()
{
// clear_interrupt(INT_TIMER0);
set_timer0(60);
//delay_ms(100);
sayi++;
if(sayi==20)
{
sum_NTC=0;
for (count_NTC=0; count_NTC<8; count_NTC++)
{
value=read_adc();
delay_us(8);
sum_NTC=value + sum_NTC;
}
avg_NTC= sum_NTC/=8;
output_high(pin_a2);
// delay_us(20);
sayi=0;
}
}
#int_timer1
void timer1_test()
{
set_timer1(60536);
mayi++;
if(mayi==100)
{
sum_CO=0;
for (count_NTC=0; count_NTC<8; count_NTC++)
{
onuf_co=read_adc();
delay_us(8);
sum_CO=onuf_co + sum_CO;
}
avg_CO= sum_CO/=8;
output_low(pin_a2);
//delay_us(20);
mayi=0;
}
}
void main()
{
//delay_ms(300);
//setup_timer_1(T1_DISABLED);
setup_timer_2(T2_DISABLED,0,1);
set_tris_c(0b00001111);// C0,C1,C2,C3 pini input yapıldı.// C4 output
set_tris_a(0x00); // a2,a4,a5 pini output //red,green,yellow leds
output_a(0x00); //red led
output_b(0x00);
output_c(0x00);
setup_adc(adc_clock_div_8);
setup_adc_ports(sAN4 |sAN7, VSS_VDD );
setup_timer_0(T0_INTERNAL | T0_DIV_256);
setup_timer_1(T1_INTERNAL | T1_DIV_BY_4);
while (true)
{
delay_ms(1000);
//======================NTC============================
set_adc_channel(4); //AN4 analog kanal
delay_us(20);
//====================================================
set_timer0(60);
enable_interrupts(INT_TIMER0);
enable_interrupts(GLOBAL);
//========================ONUF_CO=======================
set_adc_channel(7);
delay_us(20);
//===================================================
set_timer1(60536);
enable_interrupts(INT_TIMER1);
enable_interrupts(GLOBAL);
//setup_adc_ports(NO_ANALOGS);
//==================red lED==========================
if (( avg_CO >= 0) && ( avg_CO < 245) ) {
output_low(pin_a5);
delay_us(20);
}
else {
output_high(pin_a5);
delay_us(20);
}
//==================green LED ==========================
output_toggle(pin_a4);
delay_ms(500);
//==================yellow LED ==========================
//==================Stein Hart for NTC ==========================
R2 = R1 * (1023.0 / (float)avg_NTC - 1.0);
logR2 = log(R2);
T = (1.0 / (c1 + c2*logR2 + c3*logR2*logR2*logR2));
T = T - 273.15;
//==============================================================
//================== printf ==========================
// printf ("Temperature:%f ",T);
// printf("ONUF_CO-ADC= %u\n\r ",onuf_co);
// delay_ms(1000);
}
} |
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temtronic
Joined: 01 Jul 2010
Posts: 9225
Location: Greensville,Ontario
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| Posted: Fri Apr 29, 2022 5:50 am |
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I had a quick look
saw these two lines...
| Quote: |
unsigned short int onuf_co; //input_co,opamp_co,
|
this makes onuf_co a one bit variable... | Quote: |
unsigned short int avg_NTC,value,sum_NTC,sum_CO,avg_CO;
|
again variables are ONE bit wide.
| Quote: | onuf_co=read_adc();
|
this tries to put 8 or 10 but adc result into the ONE bit !
| Quote: | sum_CO=onuf_co + sum_CO;
|
this tries to add them up...BUT they're one bit wide...
also
you'll need to add 'errors' to the#USE RS232(...options...) |
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Delfinss
Joined: 05 Apr 2022
Posts: 21
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| Posted: Thu May 05, 2022 6:28 am |
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| temtronic wrote: | I had a quick look
saw these two lines...
| Quote: |
unsigned short int onuf_co; //input_co,opamp_co,
|
this makes onuf_co a one bit variable... | Quote: |
unsigned short int avg_NTC,value,sum_NTC,sum_CO,avg_CO;
|
again variables are ONE bit wide.
| Quote: | onuf_co=read_adc();
|
this tries to put 8 or 10 but adc result into the ONE bit !
| Quote: | sum_CO=onuf_co + sum_CO;
|
this tries to add them up...BUT they're one bit wide...
also
you'll need to add 'errors' to the#USE RS232(...options...) |
I think you are right but why is this happening and how can I fix it.
NTC-ADC=1 ONUF_CO-ADC= 0
NTC-ADC=1 ONUF_CO-ADC= 1 |
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Delfinss
Joined: 05 Apr 2022
Posts: 21
|
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| Posted: Thu May 05, 2022 6:38 am |
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| Ttelmah wrote: | There are also rather a lot of other problems.
He loops, changing the ADC channel. After the first pass, the interrupt
will be enabled, so the ADC will be reading different ADC channels on
some calls than others, with no synchronisation between this and the timer
calls. The values won't have any relationship to these selections...
Now he is also delaying for an enormous time inside the interrupt on the
10th and 20th calls. Why does he delay 100uSec?.
Tacq is only 7.37uSec, so 8uSec would be plenty.
The sum maths is odd:
avg_CO= sum_CO/=8;
That is not the normal syntax for the operation. It seems to be dividing
sum_CO by 8, writing this into sum_CO, and then copying this into
avg_CO. Probably will work, but an unneeded extra operation.
In the main loop, he reads the two average values, but not even one
timer interrupt will have triggered at this point. He set the count to 60, so
the timer interrupt period will be about 50mSec. He does long delays that
would allow things to happen, after having worked on the readings.
However even these are not enough to allow the 20 cycles needed to
fully generate a reading. It will take three seconds for a pass to complete.
So the first couple of times round the loop, given the avg values are
not initialised, the values will probably be overrange.
Then there is a huge problem with maths types. He has adc=10, but
uses an int for the adc value. 10bit does not go into 8bit....
He then sums this 8 times, so potentially 13bits. This doesn't fit by an
even larger margin.
Then the problem with fast_io. The ADC channels are on port A, but
he sets the whole of this port to be digital outputs.
Get rid of fast_io. It is miles safer to use standard_io (the default).
Avoids this sort of error.
I gave up at this point.... |
| Code: | #include <16f1509.h>
#device ADC = 10 // 0 ile 1023
#include <math.h>
#use delay(internal=4000000)
#fuses INTRC_IO ,NOWDT ,NOPUT ,NOLVP ,NOPROTECT ,NODEBUG ,NOBROWNOUT ,NOWRT
#use standard_io(c)
#use standard_io(a)
#use rs232 (baud=9600, xmit=pin_B7,rcv=pin_B5, parity=N, stop=1)
int count_NTC;
int sayi=0;
int mayi=0;
unsigned short int avg_NTC,sum_NTC,sum_CO,avg_CO;
unsigned int onuf_co,value;
float R1 = 22000;
float logR2, R2, T;
float c1 = 0.5699030023e-03, c2 = 2.830523628e-04, c3 = -1.761701742e-07;
#int_timer0
void timer0_test()
{
// clear_interrupt(INT_TIMER0);
set_timer0(60);
//delay_ms(100);
sayi++;
if(sayi==60)
{
sum_NTC=0;
for (count_NTC=0; count_NTC<8; count_NTC++)
{
value=read_adc();
delay_us(8);
sum_NTC=value + sum_NTC;
}
avg_NTC= sum_NTC/=8;
printf("NTC-ADC=%u ", value);
delay_us(10);
output_high(pin_a2);
// delay_us(20);
sayi=0;
}
}
#int_timer1
void timer1_test()
{
set_timer1(60536);
mayi++;
if(mayi==150)
{
sum_CO=0;
for (count_NTC=0; count_NTC<8; count_NTC++)
{
onuf_co=read_adc();
delay_us(8);
sum_CO=onuf_co + sum_CO;
}
avg_CO= sum_CO/=8;
printf("ONUF_CO-ADC= %u\n\r ",onuf_co);
delay_us(10);
output_low(pin_a2);
//delay_us(20);
mayi=0;
}
}
void main()
{
//delay_ms(300);
//setup_timer_1(T1_DISABLED);
setup_timer_2(T2_DISABLED,0,1);
set_tris_c(0b00001111);
set_tris_a(0x00);
output_a(0x00); //red led
output_b(0x00);
output_c(0x00);
setup_adc(adc_clock_div_8);
setup_adc_ports(sAN4 |sAN7, VSS_VDD );
setup_timer_0(T0_INTERNAL | T0_DIV_256);
setup_timer_1(T1_INTERNAL | T1_DIV_BY_4);
while (true)
{
delay_ms(1000);
//======================NTC============================
set_adc_channel(4); //AN4 analog kanal
delay_us(20);
//====================================================
set_timer0(60);
enable_interrupts(INT_TIMER0);
enable_interrupts(GLOBAL);
setup_adc_ports(NO_ANALOGS);
//========================ONUF_CO=======================
delay_ms(1000);
set_adc_channel(7);
delay_us(20);
//===================================================
set_timer1(60536);
enable_interrupts(INT_TIMER1);
enable_interrupts(GLOBAL);
setup_adc_ports(NO_ANALOGS); |
I used timer0 and timer1 for the sequencing problem.
as a result i am not getting the ADC values. |
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temtronic
Joined: 01 Jul 2010
Posts: 9225
Location: Greensville,Ontario
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| Posted: Thu May 05, 2022 7:33 am |
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Here's part of your problem...
| Quote: | unsigned short int avg_NTC,sum_NTC,sum_CO,avg_CO;
|
You've declared ALL these variables to be ONE bit ( '1' or '0' )
| Quote: | unsigned int onuf_co,value;
|
These are 8 bit values, yet ADC is declared as 10 bit.
Until you change these to the proper declarations you'll never get to read and do 'math' properly. |
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Ttelmah
Joined: 11 Mar 2010
Posts: 19504
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| Posted: Thu May 05, 2022 11:47 am |
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Yes, I pointed out that his variable sizes were too small at the start, and
instead of making them bigger, he has made them smaller!...
int1
int
int16
int32
Is the order of sizes. He started at int, and went to int1, instead of
to int16 or int32. |
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Delfinss
Joined: 05 Apr 2022
Posts: 21
|
| TİMER0 and ADC with 16F1509 |
| Posted: Tue May 10, 2022 12:37 am |
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|
Hello again everyone
I tried to simplify the code. but tell me i ran into a problem.
When I use standard_io I get the ADC value of 1.
When I use fast_io I read the ADC value normally.
where is the problem? can you help me?
| Code: | #include <16f1509.h>
#device ADC = 10 // 0 ile 1023
#include <math.h>
#use delay(internal=4000000)
#fuses INTRC_IO ,NOWDT ,NOPUT ,NOLVP ,NOPROTECT ,NODEBUG ,NOBROWNOUT ,NOWRT
#use standard_io(C)
#use standard_io(A)
#use rs232 (baud=9600, xmit=pin_B7,rcv=pin_B5, parity=N, stop=1)
int sayi=0;
int16 value;
float R1 = 22000;
float logR2, R2, T;
float c1 = 0.5699030023e-03, c2 = 2.830523628e-04, c3 = -1.761701742e-07;
#int_timer0
void timer0_test()
{
set_timer0(60); // 50 ms
sayi++;
if(sayi==40) // 50*40 =2000 ms(2sn)
{
value=read_adc();
delay_us(8);
printf("NTC-ADC= %lu\n\r ", value);
delay_us(10);
output_toggle(pin_a2);
sayi=0;
}
}
void main()
{
setup_timer_1(T1_DISABLED);
setup_timer_2(T2_DISABLED,0,1);
output_a(0x00); //red led
output_c(0x00);
setup_adc(adc_clock_div_8);
setup_adc_ports(sAN4 |sAN7, VSS_VDD );
setup_timer_0(T0_INTERNAL | T0_DIV_256);
// set_tris_a(0x00);
//set_tris_c(0b00001111);
while (true)
{
//======================NTC============================
set_adc_channel(4); //AN4 analog kanal
delay_us(20);
// read_adc(ADC_START_ONLY);
//=========================================================
set_timer0(60);
enable_interrupts(INT_TIMER0);
enable_interrupts(GLOBAL);
//==================green LED ==========================
output_high(pin_a4);
// delay_ms(500);
//==================Stein Hart for NTC ==========================
R2 = R1 * (1023.0 / (float) value- 1.0);
logR2 = log(R2);
T = (1.0 / (c1 + c2*logR2 + c3*logR2*logR2*logR2));
T = T - 273.15;
//==============================================================
//================== printf ==========================
delay_ms(2000);
printf ("Temperature:%f\n\r ",T);
}
} |
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PCM programmer
Joined: 06 Sep 2003
Posts: 21708
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| Posted: Tue May 10, 2022 12:47 am |
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|
When using standard i/o the statement above will set the TRIS to
be all outputs on PortC.
You want pins C0 and C3 to be inputs for the ADC function.
You can do this with:
| Code: |
output_c(0x00);
set_tris_c(0x09); // Set pins C0 and C3 to be inputs
|
or
| Code: |
output_c(0x00);
output_float(PIN_C0); // Set pin C0 as input
output_float(PIN_C3); // Set pin C3 as input
|
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Delfinss
Joined: 05 Apr 2022
Posts: 21
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| Posted: Tue May 10, 2022 2:03 am |
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PCM programmer thank you for some previous info
now i get 1 value when reading 2 adc values
where is the problem? can you help me?
| Code: | #include <16f1509.h>
#device ADC = 10 // 0 ile 1023
#include <math.h>
#use delay(internal=4000000)
#fuses INTRC_IO ,NOWDT ,NOPUT ,NOLVP ,NOPROTECT ,NODEBUG ,NOBROWNOUT ,NOWRT
#use standard_io(C)
#use standard_io(A)
#use rs232 (baud=9600, xmit=pin_B7,rcv=pin_B5, parity=N, stop=1)
int sayi=0;
unsigned int16 value,value2;
float R1 = 22000;
float logR2, R2, T;
float c1 = 0.5699030023e-03, c2 = 2.830523628e-04, c3 = -1.761701742e-07;
#int_timer0
void timer0_test()
{
set_timer0(60); // 50 ms }
sayi++;
if(sayi==40) // 50*40 =2000 ms(2sn)
{
value=read_adc();
delay_us(8);
printf("NTC-ADC= %lu\n\r ", value);
delay_us(10);
output_high(pin_a2);
}
if(sayi==80) // 50*80 =4000 ms(4sn)
{
value2=read_adc();
delay_us(8);
printf("CO-ADC= %lu\n\r ", value2);
delay_us(10);
output_low(pin_a2);
sayi=0;
}
}
void main()
{
setup_timer_1(T1_DISABLED);
setup_timer_2(T2_DISABLED,0,1);
output_a(0x00); //red led
output_c(0x00);
set_tris_a(0x00);
set_tris_c(0x09); // C0 and C3 input
//output_float(PIN_C0); // Set pin C0 as input
//output_float(PIN_C3); // Set pin C3 as input
setup_adc(adc_clock_div_8);
setup_adc_ports(sAN4 |sAN7, VSS_VDD );
setup_timer_0(T0_INTERNAL | T0_DIV_256);
while (true)
{
//===================================
set_adc_channel(4); //AN4
delay_us(20);
// read_adc(ADC_START_ONLY);
//=========================================================
set_timer0(60);
enable_interrupts(INT_TIMER0);
enable_interrupts(GLOBAL);
//===========================================
set_adc_channel(7); //AN7
delay_us(20);
// read_adc(ADC_START_ONLY);
//=====================================
set_timer0(60);
enable_interrupts(INT_TIMER0);
enable_interrupts(GLOBAL);
//==================green LED ==========================
output_high(pin_a4);
// delay_ms(500);
//==================Stein Haavg_NTC rt for NTC ==========================
R2 = R1 * (1023.0 / (float) value- 1.0);
logR2 = log(R2);
T = (1.0 / (c1 + c2*logR2 + c3*logR2*logR2*logR2));
T = T - 273.15;
//==============================================================
//
//================== printf ==========================
delay_ms(2000);
printf ("Temperature:%f\n\r ",T);
}
}
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PCM programmer
Joined: 06 Sep 2003
Posts: 21708
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| Posted: Tue May 10, 2022 2:43 am |
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| Quote: | set_adc_channel(4); //AN4
delay_us(20);
// read_adc(ADC_START_ONLY);
//===========================================
set_timer0(60);
enable_interrupts(INT_TIMER0);
enable_interrupts(GLOBAL);
//===========================================
set_adc_channel(7); //AN7
delay_us(20);
// read_adc(ADC_START_ONLY);
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In the code above you are setting the adc channel before reading
each channel, but you're not actually reading the channels.
In the code below, you have two adc reads, but you are not
setting the channel before each read. Because of this you're
going to read the same thing for each read.
Before you read the ADC you should set the desired channel and
wait at least 5 usec. Then read the ADC.
| Quote: |
if(sayi==10)
{
sum_NTC=0;
for (count_NTC=0; count_NTC<8; count_NTC++)
{
value=read_adc();
delay_us(100); // This delay does nothing. Delete it.
sum_NTC=value + sum_NTC;
}
avg_NTC= sum_NTC/=8;
output_high(pin_a2);
// delay_us(20);
}
if(sayi==20)
{
sum_CO=0;
for (count_NTC=0; count_NTC<8; count_NTC++)
{
onuf_co=read_adc();
delay_us(100); // This delay does nothing. Delete it.
sum_CO=onuf_co + sum_CO;
}
avg_CO= sum_CO/=8;
output_low(pin_a2);
//delay_us(20);
sayi=0;
}
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Delfinss
Joined: 05 Apr 2022
Posts: 21
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| Posted: Tue May 10, 2022 3:24 am |
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temperature:22.45
NTC-ADC = 339
CO-ADC = 1
I couldn't read channel 7 again
| Quote: | #int_timer0
void timer0_test()
{
set_timer0(60); // 50 ms }
sayi++;
if(sayi==20) // 50*40 =2000 ms(2sn)
{
set_adc_channel(4); //AN4
delay_us(5);
value=read_adc();
delay_us(8); // for Tacq
// setup_adc( ADC_OFF );
printf("NTC-ADC= %lu\n\r ", value);
delay_us(10);
output_high(pin_a2);
}
if(sayi==40) // 50*80 =4000 ms(4sn)
{
set_adc_channel(7); //AN7
delay_us(5);
value2=read_adc();
delay_us(8); // for Tacq
printf("CO-ADC= %lu\n\r ", value2);
delay_us(10);
output_low(pin_a2);
sayi=0;
}
}
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