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Jhonny
Joined: 30 Jan 2011
Posts: 16
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| Output_bit , nothing |
 Posted: Fri Mar 27, 2015 8:42 am |
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Hi!
I use this code:
| Code: |
#include <12F683.h>
#device ADC=16
#FUSES NOWDT //No Watch Dog Timer
#FUSES noPUT //Power Up Timer
#FUSES PROTECT //Code protected from reads
#FUSES NOBROWNOUT //No brownout reset
#FUSES NOIESO //Internal External Switch Over mode disabled
#FUSES NOFCMEN //Fail-safe clock monitor disabled
#use delay(internal=4000000)
int16 i;
unsigned int16 data=0b0101010101010101;
void main()
{
while(TRUE)
{
for(i=1;i<=16;++i)
{
output_bit(PIN_A5, shift_left(data,2,1));
delay_ms(30);
}
i=0;
delay_ms(500);
}//end while
}//end main
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The output signal is continuous H level. What is wrong? (I'm going crazy ...)  |
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Ttelmah
Joined: 11 Mar 2010
Posts: 19515
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| Posted: Fri Mar 27, 2015 9:19 am |
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After 480mSec, it will be.
You are shifting a 1 in every time, so after 16shifts, data will contain all 1's....
| Code: |
void main()
{
unsigned int16 temp;
while(TRUE)
{
temp=data;
for(i=0;i<16;++i)
{
output_bit(PIN_A5, shift_left(&temp,2,1));
delay_ms(30);
}
delay_ms(500);
}//end while
}//end main
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This way the value to shift is reloaded every loop.
Remember also 'shift_left' requires an _address_. Note the '&'.
Last edited by Ttelmah on Fri Mar 27, 2015 11:44 am; edited 1 time in total |
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Jhonny
Joined: 30 Jan 2011
Posts: 16
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| Posted: Fri Mar 27, 2015 10:13 am |
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Okay, I begin to understand. Thank you very much, it seems to me that we have to work well.  |
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