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subtraction signed int8

 
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hmmpic



Joined: 09 Mar 2010
Posts: 314
Location: Denmark

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subtraction signed int8
PostPosted: Tue Oct 21, 2014 1:14 pm     Reply with quote

This is only a test program.

I have tested it in MPLAB V8.92. with the simulator.
It is compiled in CCS 5.027! and tested in real hardware (not the posted code)


Only the first OK1 is working all the other fail! But why?

I am Confused.



Code:
#include <18F26k22.h>
#use delay(clock=8M,int)
#use RS232(Baud=57600,STOP=1,PARITY=N,BITS=8,UART1,ERRORS,stream=sim900)


/*Max dif: ad-adtmp=+-5 adtmp-ad=+-5*/
void GetTemp2(){
 int8 ok=0;
 int8 ad,adtmp;
 int8 cnt;

 ad=127;
 adtmp=127;

 for (cnt=0; cnt<10; cnt++){
  ad++; /* Test with ad--, ad++, adtmp--, adtmp++ */
  printf("AD:%u ADTmp:%u Cnt:%u\r\n",ad,adtmp,cnt);

  ok=0;
  if ( (((signed int8)ad-adtmp)<5) && (((signed int8)ad-adtmp)>-5) ) {ok=1;}
  printf("OK1:%u\r\n",ok);

  ok=0;
  if ( ((-adtmp+ad)<5) && ((-adtmp+ad)>-5) ) {ok=1;}
  printf("OK2:%u\r\n",ok);

  ok=0;
  if ( ((ad+(-adtmp))<5) && ((ad+(-adtmp))>-5) ) {ok=1;}
  printf("OK3:%u\r\n",ok);

  ok=0;
  if ( ((ad+(-adtmp))<5) && ((adtmp+(-ad))<5) ) {ok=1;}
  printf("OK4:%u\r\n",ok);
 
  printf("******\r\n");
 }
}


void main() {
 GetTemp2();
}
Ttelmah



Joined: 11 Mar 2010
Posts: 19513

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PostPosted: Tue Oct 21, 2014 1:23 pm     Reply with quote

A signed int8, can hold values from -128 to +127.
An unsigned int8, uses the same storage to hold 0 to 255.
You start at 127.
Then increment - now have 128. When this is converted to a signed int8, you get -1.
Then increment again - now have 129. When this is converted to a signed int8, you have -2.

etc. etc.

You are overflowing the signed int8 arithmetic, just about everywhere....
hmmpic



Joined: 09 Mar 2010
Posts: 314
Location: Denmark

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PostPosted: Tue Oct 21, 2014 2:06 pm     Reply with quote

Now I ended up with this working on:
Code:
if (ad>adtmp) { ok=(ad-adtmp)<5; } else { ok=(adtmp-ad)<5; }


Thanks for hints on the overflow:-)
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