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UART problem - always received data is FF?!

 
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stoyanoff



Joined: 20 Jul 2011
Posts: 375

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UART problem - always received data is FF?!
PostPosted: Tue Jan 15, 2013 2:45 am     Reply with quote

Hi, everyone! I made a simple pcb with 2 micros (18F2550 and 16F648A). I made simple programs for each of them - 18F2550 master and 16F648A slave:
Slave
Code:

#include <16F648A.h>
#FUSES HS,NOWDT
#use delay(clock=20M)
#use rs232(baud=9600,parity=N,xmit=pin_B2,rcv=PIN_B1,stream=RS232,bits=8,errors)

void main()
{
   delay_ms(1000);
   while(1)
   {
      putc('0');
      delay_ms(1000);
   }
}


Master:
Code:

#include <18F2550.h>
#fuses HS,NOWDT
#use delay(clock=20M)
#use rs232(baud=9600,parity=N,xmit=pin_C6,rcv=PIN_C7,stream=RS232,bits=8,errors)

char data;
void main()
{
   delay_ms(1000);
   while(1)
   {
      data=1;
      if(kbhit())
      {
         data=getc();
         delay_ms(1000);//break point here
      }
   }
}

I connected pin 18 (RX) of 18F2550 to pin 8 (TX) of 16F648A. I'm using PicKit 3 as debugger. The program is entering into the "if" statement, but the value of data is always 0xFF.
What am I doing wrong?
Thanks!
Ttelmah



Joined: 11 Mar 2010
Posts: 19535

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PostPosted: Tue Jan 15, 2013 3:03 am     Reply with quote

OK. This suggests that one or the other chip is not clocking at the speed you think it is. Your 2550, won't be running at 20MHz. Reason is that you are not setting the CPUDIV divider, and this defaults to 4. So the 2550, is running at 5MHz, and is clocking the data in at 1/4 the rate it should be. Add the fuse CPUDIV1 to the ones selected for this chip, and see if things improve. Smile

You can check this, by looking at the .lst file. With your fuses, you get:
Code:

Configuration Fuses:
   Word  1: CC3F   PLL12 CPUDIV4 USBDIV HS FCMEN IESO
   Word  2: 1E3E   PUT BROWNOUT BORV21 VREGEN NOWDT WDT32768
   Word  3: 8700   CCP2C1 PBADEN LPT1OSC MCLR
   Word  4: 0081   STVREN NOLVP NOXINST NODEBUG
   Word  5: C00F   NOPROTECT NOCPB NOCPD
   Word  6: E00F   NOWRT NOWRTC NOWRTB NOWRTD
   Word  7: 400F   NOEBTR NOEBTRB


It's clocking it's LSb in six bit times after the falling edge, which with '0' sent (binary 00001100), just happens to be in the two 1's, so a 1 is clocked in, then the rest of the bits are all clocked after the byte has finished, when the line has returned to 'high', so 1's are then clocked in for everything else. Hence 0xFF.

Best Wishes
stoyanoff



Joined: 20 Jul 2011
Posts: 375

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PostPosted: Tue Jan 15, 2013 4:46 am     Reply with quote

That`s it! Thanks, again Ttelmah!
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