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Lukas89
Joined: 06 May 2012 Posts: 2
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converting integer to character |
Posted: Sun May 06, 2012 3:20 pm |
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Hello,
I'm using PIC18F4550 and hyperterminal communication via USB. I want to convert integer value to character, it's for displaying in LabView graph. Code I'm using is below:
Code: |
void main(){
int a=25;
char str [33],RcvUSB;
usb_cdc_init();
usb_init();
do {
usb_task();
if (usb_enumerated()) {
RcvUSB=usb_cdc_getc();
if(RcvUSB='q'){
printf(usb_cdc_putc,"\n\r%c", RcvUSB);
itoa(a,str,10);
printf(usb_cdc_putc,"\n\rdecimal = %s",str);
itoa(a,str,2);
printf(usb_cdc_putc,"\n\rbinary = %s",str);
itoa(a,str,16);
printf(usb_cdc_putc,"\n\rhexademical = %s",str);
}while(TRUE)
} |
OUTPUT(copy from terminal):
q
decimal =
binary =
hexademical =
I got unreadable character, in fact somehow its looks like smileface. I tried to use %c, %d instead of %s, but nothing seemed working. I will appreciate for your attention. |
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jeremiah
Joined: 20 Jul 2010 Posts: 1328
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Posted: Sun May 06, 2012 4:21 pm |
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you need to look at itoa in the compiler manual again. Specifically the parameter order. |
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Lukas89
Joined: 06 May 2012 Posts: 2
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Posted: Sun May 06, 2012 4:38 pm |
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Indeed, the order was wrong. Looked at itoa function and changed code:
Code: |
void main(){
char RcvUSB;
usb_cdc_init();
usb_init();
do {
usb_task();
if (usb_enumerated()) {
RcvUSB=usb_cdc_getc();
if(RcvUSB='q'){
int32 a=25;
char str [33];
printf(usb_cdc_putc,"\n\r%c", RcvUSB);
itoa(a,10,str);
printf(usb_cdc_putc,"\n\rdecimal = %s",str);
itoa(a,2,str);
printf(usb_cdc_putc,"\n\rbinary = %s",str);
itoa(a,16,str);
printf(usb_cdc_putc,"\n\rhexademical = %s",str);
}while(TRUE)
} |
OUTPUT(copy from terminal):
q
decimal = 25
binary = 11001
hexademical = 19
Thanks jeremiah. |
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