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Memory not available at requested location

 
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martint88



Joined: 11 Feb 2011
Posts: 5

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Memory not available at requested location
PostPosted: Mon Jun 13, 2011 2:26 pm     Reply with quote

Hello,

I'm trying to use the program memory to save the my system configuration. For the factory defaults, I use the following code:

Code:

#rom int8 0x1FC00={0x01,0x00,0x00,0x00,0x00,0x00,0x00,0x00}


When compiling, I receive the "Memory not available at requested location" warning, but in the disassembly, I get the memory correctly initialized.
I'm using PIC18F47J13, and CCS Version 4.110

I also get this warning in the following lines:

Code:

union Bits_Sueltos
{
   int8 Palabra;
   int1 Flags[8];
};
typedef union Bits_Sueltos tipo_Bits;



Is this the correct way to tell the linker not to use this memory for code?
What is this warning?

Thankyou
regards,
Martin
PCM programmer



Joined: 06 Sep 2003
Posts: 21708

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PostPosted: Mon Jun 13, 2011 2:39 pm     Reply with quote

Quote:

When compiling, I receive the "Memory not available at requested location" warning.

I made a test program and I don't get any warning like that in either
Debug or Release configuration:
Code:

Executing: "C:\Program Files\PICC\Ccsc.exe" +FH "PCH_Test.c" +DF +LY  -T -A +M -Z +Y=9 +EA #__18F47J13=TRUE
>>> Warning 203 "PCH_Test.c" Line 12(1,1): Condition always TRUE
      Memory usage:   ROM=0%      RAM=0% - 0%
      0 Errors,  1 Warnings.
Loaded C:\Program Files\PICC\Projects\PCH_Test\PCH_Test.cof.
BUILD SUCCEEDED: Mon Jun 13 13:34:03 2011

------------
List file:

CCS PCH C Compiler, Version 4.110, xxxxx     13-Jun-11 13:34

               Filename: C:\Program Files\PICC\Projects\PCH_Test\PCH_Test.lst

               ROM used: 48 bytes (0%)
                         Largest free fragment is 65496
               RAM used: 4 (0%) at main() level
                         4 (0%) worst case
               Stack:    0 locations

Here is the test program:
Code:

#include <18F47J13.h>
#fuses HS,NOWDT
#use delay(clock=4000000)

#rom int8 0x1FC00={0x01,0x00,0x00,0x00,0x00,0x00,0x00,0x00}

//=====================
void main()
{
   
while(1);
}


You should do your typedef like this:
Code:

typedef union
{
   int8 Palabra;
   int1 Flags[8];
}Bits_Sueltos;
 
Bits_Sueltos tipo_Bits;
Ttelmah



Joined: 11 Mar 2010
Posts: 19318

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PostPosted: Mon Jun 13, 2011 2:54 pm     Reply with quote

The warning on the union, is probably because 'arrays of bits are not permitted'.....

Best Wishes
martint88



Joined: 11 Feb 2011
Posts: 5

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PostPosted: Tue Jun 14, 2011 5:49 am     Reply with quote

I could solve the problem on the warning, but:
is it true I can´t use arrays of bits? I think I Can in version 4.110...
What i found it doesn´t work is to asign a bit from an array to another bit, as follows:

Code:


int1 flag;
int1 flag2[10];
int8 i;

for (i = 0; i < 10; i++)
{
       flag = flag2[i];    // this seems not working.
}



That´s why, i had to replace all bit arrays I used by another code.

Thank you for your help

regards,
Martin
dyeatman



Joined: 06 Sep 2003
Posts: 1922
Location: Norman, OK

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PostPosted: Tue Jun 14, 2011 5:58 am     Reply with quote

From the manual on page 43:
Quote:
SHORT is a special type used to generate very efficient code for bit
operations and I/O. Arrays of bits (INT1 ) in RAM are now supported.
Pointers to bits are not permitted.

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