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cerr
Joined: 10 Feb 2011
Posts: 241
Location: Vancouver, BC
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| int1 problem |
 Posted: Wed Mar 09, 2011 6:58 pm |
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Hi There,
I have an int1 in a function and initialize it with 0 and in MPLAB debugger (ICD3) it shows me a value of 0x5C - how can that be??? 
Thanks,
Ron |
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bkamen
Joined: 07 Jan 2004
Posts: 1615
Location: Central Illinois, USA
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| Posted: Thu Mar 10, 2011 2:22 am |
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if I remember right, CCS packs INT1's into a byte...
MPLAB shows you the byte... can you expand it to see the bits within?
I'd have to do a check myself to see.. but off the top of my head...
-Ben
_________________
Dazed and confused? I don't think so. Just "plain lost" will do. :D |
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cerr
Joined: 10 Feb 2011
Posts: 241
Location: Vancouver, BC
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| Posted: Thu Mar 10, 2011 10:47 am |
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Yes I can see the bits withinand okay, 0x5C bit0 is 0 but you cant expect this to go the way you would expect:
int1 x=0;
if (x){
// it'll go here;
}else{
// but i would expect it here;
}
Why would I need to apply a mask 0x01 to a variable I declared to be 1 bit long only?
Seems like I don't see through but... |
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bkamen
Joined: 07 Jan 2004
Posts: 1615
Location: Central Illinois, USA
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| Posted: Thu Mar 10, 2011 11:00 am |
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| cerr wrote: | Yes I can see the bits withinand okay, 0x5C bit0 is 0 but you cant expect this to go the way you would expect:
int1 x=0;
if (x){
// it'll go here;
}else{
// but i would expect it here;
}
Why would I need to apply a mask 0x01 to a variable I declared to be 1 bit long only?
Seems like I don't see through but... |
You don't need to mask. It's MPLAB's interpretation to display.
I use 1bit int's all the time in CCS and they work fine as you'd expect.
If you want.... do that If-Then and then look at the asm.. you'll see it's as efficient as you'd expect with a bit testing instructions rather than loading up WREG and testing that.
-Ben
_________________
Dazed and confused? I don't think so. Just "plain lost" will do. :D |
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