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Guest
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int_tbe problems |
Posted: Fri Feb 22, 2008 4:06 pm |
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Im using a PIC16F688, and compiler v. 4.058.
Ive got a fairly large program, and Im trying to implement the hardware uart. I cant get it to work. Its definitely too much code to post. The problem is that the transmitter buffer interrupt never fires. I made a simple test program using the code wizard, and still no luck getting into int_tbe.
Code: |
#include <16F688.h>
#device adc=8
#FUSES INTRC_IO, NOWDT, PUT, MCLR, BROWNOUT_NOSL, NOPROTECT, NOCPD, NOIESO, NOFCMEN
#use delay(clock=8000000,RESTART_WDT)
#use rs232(baud=9600,parity=N,xmit=PIN_A4,rcv=PIN_A2,bits=8,enable=PIN_A0)
#int_TBE
void TBE_isr(void)
{
output_toggle(PIN_C5); // flashes an LED
}
void main()
{
output_high(PIN_C2); // latches my power supply
enable_interrupts(INT_TBE);
enable_interrupts(GLOBAL);
while(1)
{
}
}
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Am I misunderstanding how int_tbe works? It should be called over and over again since its not being disabled right? |
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PCM programmer
Joined: 06 Sep 2003 Posts: 21708
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Posted: Fri Feb 22, 2008 4:38 pm |
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It only works with the hardware UART. You must specify the hardware
UART pins in the #use rs232() statement. For the 16F688, these are
pins C4 and C5, for Tx and Rx.
The hardware UART module is disabled by default upon power-on reset.
Because you specified non-hardware UART pins, the code to enable it
will not be generated by the compiler. The UART will remain disabled,
and no TBE interrupt will ever occur. |
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Guest
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Posted: Sat Feb 23, 2008 11:28 pm |
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So if I use the non-hardware uart pins, I have to use the software uart? If the software doesnt use interrupts, how does the receiver know when its receiving a character? |
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newguy
Joined: 24 Jun 2004 Posts: 1908
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Posted: Sun Feb 24, 2008 1:05 am |
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It doesn't. You have to continually monitor it. |
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meereck
Joined: 09 Nov 2006 Posts: 173
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Posted: Sun Feb 24, 2008 3:52 am |
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Anonymous wrote: | So if I use the non-hardware uart pins, I have to use the software uart? If the software doesnt use interrupts, how does the receiver know when its receiving a character? |
You can connect the software receive pin to an external interrupt trigger pin and set L_TO_H event up. After that, int_ext routine will be called, and you can read the received character after that. |
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Ttelmah Guest
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Posted: Sun Feb 24, 2008 9:45 am |
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You would actually want a H_TO_L event. The start bit in TTL asynchronous serial, is a _low_.
Best Wishes |
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Douglas Kennedy
Joined: 07 Sep 2003 Posts: 755 Location: Florida
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Posted: Sun Feb 24, 2008 1:33 pm |
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Ttelmah wrote
Quote: | You would actually want a H_TO_L event. The start bit in TTL asynchronous serial, is a _low_. |
This is important issue that Ttelmah points out.
I had a 12F683 no hardware (UART ) . I can catch chars in my main loop with the true and tried khbit getc approach so there was no pressing issue forcing an interrupt driven design. Anyway I tried it anyway. The 12F683 has interrupt on change that can be masked down to specific pins. Now the change is both high low and low high. I never got this to work reliably and it might be to do with the dual edge triggering. I abandoned the design since to use the EXT_INT pin would have required a pcb change and the non interrupt code works fine.
Ttelmah any opinion on what is needed to use the interrupt on change assuming its possible? |
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Ttelmah Guest
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Posted: Sun Feb 24, 2008 3:34 pm |
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Big problem is speed.
The edge 'event' will occur on the falling edge of the data bit. Even if no other interrupt handlers are present, you are talking something over 30 instruction times to actually reach the handler code. If you want to avoid a 'lockup' condition (if a spike triggers an edge, when no real data is present), you will need to have a kbhit, test then the actual read code. Now this is therefore going to be starting something like 40 instruction times _after_ the start of the character. At 4Mhz, and 9600bps, the 'bit time', is only 104 instructions. The read routine, by default, delays for half a bit time, before starting to sample the data (52 instructions in this example), meaning that you are now _very_ late in the bit. Only a small timing error, is then needed to give data errors....
The latter compilers, have an option 'SAMPLE_EARLY' for the software UART, which is really best used in this situation.
With a faster clock, or a lower baud rate, the problem reduces/disappears.
Remember also, that if you want to use a software UART to transmit data at the same time, the data on this, _will_ be corrupted, as soon as a character is received.
Best Wishes |
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Douglas Kennedy
Joined: 07 Sep 2003 Posts: 755 Location: Florida
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Posted: Sun Feb 24, 2008 5:53 pm |
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Thanks Ttelmah for an excellent description. I wish I had tried SAMPLE_EARLY. I'm going to go back and give it a try.
Inside the interrupt on change isr I plan to be doing something this
If ( KBhit()) circ_buff[received_index++]=getc();
I'm at 4mhz on the internal osc rs232 is 9600 baud. |
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muratmaman
Joined: 30 Jan 2010 Posts: 19
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Posted: Thu Nov 11, 2010 12:42 am |
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Douglas Kennedy wrote: | Thanks Ttelmah for an excellent description. I wish I had tried SAMPLE_EARLY. I'm going to go back and give it a try.
Inside the interrupt on change isr I plan to be doing something this
If ( KBhit()) circ_buff[received_index++]=getc();
I'm at 4mhz on the internal osc rs232 is 9600 baud. |
Dear All,
I have been trying to run below interrupts in my software but it was not working. I am stuck. Anyone can help me solve this problem?
I used the above software and just added
INT_TIMER1, INT_RB, INT_EXT, INT_TBE, INT_RDA.
When I enabled all of them in this case, just INT_RDA and INT_TBE was working however other interrupts was not working. Not fired any time.
I'm using a PIC16F688, and compiler v. 4.058. Also Ttelmah mentioned to use SAMPLE_EARLY but again same stuation.
What can I do ? _________________ I have been developing pic and other microcontroller. I would want to share and get experiment form this site |
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