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tonkostz
Joined: 07 May 2011
Posts: 40
Location: Bulgaria
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| Help with internal eeprom programming algorithm |
 Posted: Thu Sep 06, 2012 10:59 am |
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I'm trying to make a program to count button pushes and depending on the result, to program the internal eeprom with different values.
For example:4 pushes of the button - value=1
5 pushes of the same button - value=2
6 pushes of the same button - value=3.
I made this program i don't know how to reset the i variable (i=0) when i=4. I mean that if i continue pushing the button next time i=5 and next i=6.
I want to make the program to count to 4 (for 4 button pushes), write eeprom. Next time i want to push the button 5 times write the other value and next, another 6 times to write the last value to the eeprom.
I'm not sure i managed to explain what i want. I hope you understand.
| Code: |
if(input(PIN_A5)==1)
{
i++;
if(i>6)
i=6;
while(input(PIN_A5)) //loop here until button released.
{
delay_ms(20);
}
if(i==4)
{
write_int16_eeprom(u4,0);
}
if(i==5)
{
write_int16_eeprom(u4,1);
}
if(i==6)
{
write_int16_eeprom(u4,2);
}
} |
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Gabriel
Joined: 03 Aug 2009
Posts: 1067
Location: Panama
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| Posted: Thu Sep 06, 2012 11:19 am |
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IF i understood correctly, then:
where you declare "i":
//<--- start at 3 since you do i++ as soon as you enter your button function.
and then...
| Code: | if(input(PIN_A5)==1)
{
i++;
if(i>6)
i=4; //<---------- effectively now your allowed values will be 4,5,6 only.
while(input(PIN_A5)) //loop here until button released.
{
delay_ms(20);
}
if(i==4)
{
write_int16_eeprom(u4,0);
}
if(i==5)
{
write_int16_eeprom(u4,1);
}
if(i==6)
{
write_int16_eeprom(u4,2);
}
} |
_________________
CCS PCM 5.078 & CCS PCH 5.093 |
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tonkostz
Joined: 07 May 2011
Posts: 40
Location: Bulgaria
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| Posted: Thu Sep 06, 2012 11:30 am |
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It seems like i did not manage to explain correctly what i want. I'll try again.
I push the button 4 times and 0 is written to the eeprom.
Next time i want to push the button 5 times to write 1 and 6 times to write 2. This is what i want.
My current program is doing something else:I push 4 times the button and i=4. Next pushes start from 4, so only 1 push is needed to reach i=5 and 2 pushes to reach 6.
I want after the first 4 pushes i variable to be reset to 0 (i=0). |
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Mike Walne
Joined: 19 Feb 2004
Posts: 1785
Location: Boston Spa UK
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| Posted: Fri Sep 07, 2012 2:20 am |
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I think you need a time-out on your button function.
Start the button function with i=0.
If a button has been pressed within the time out, i++.
If a button has not been pressed within the time limit you've finished.
When finished, store required value to eeprom.
Mike
EDIT Beware of wearing out your eeprom! |
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tonkostz
Joined: 07 May 2011
Posts: 40
Location: Bulgaria
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| Posted: Fri Sep 07, 2012 6:27 am |
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| Mike Walne wrote: | I think you need a time-out on your button function.
Start the button function with i=0.
If a button has been pressed within the time out, i++.
If a button has not been pressed within the time limit you've finished.
When finished, store required value to eeprom.
Mike
EDIT Beware of wearing out your eeprom! |
Do i need to use interrupts or some button interrupt code for that? |
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Gabriel
Joined: 03 Aug 2009
Posts: 1067
Location: Panama
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| Posted: Fri Sep 07, 2012 6:31 am |
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Ah!
then this maybe...
(i didnt test it)
| Code: | if(input(PIN_A5)==1)
{
i++;
if(i>6)
i=6;
while(input(PIN_A5)) //loop here until button released.
{
delay_ms(20);
}
if(i==4)
{
write_int16_eeprom(u4,0);
i=0;
}
if(i==5)
{
write_int16_eeprom(u4,1);
i=0;
}
if(i==6)
{
write_int16_eeprom(u4,2);
i=0;
}
} |
...
G
_________________
CCS PCM 5.078 & CCS PCH 5.093 |
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tonkostz
Joined: 07 May 2011
Posts: 40
Location: Bulgaria
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| Posted: Fri Sep 07, 2012 6:52 am |
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| Gabriel wrote: | Ah!
then this maybe...
(i didnt test it)
| Code: | if(input(PIN_A5)==1)
{
i++;
if(i>6)
i=6;
while(input(PIN_A5)) //loop here until button released.
{
delay_ms(20);
}
if(i==4)
{
write_int16_eeprom(u4,0);
i=0;
}
if(i==5)
{
write_int16_eeprom(u4,1);
i=0;
}
if(i==6)
{
write_int16_eeprom(u4,2);
i=0;
}
} |
...
G |
I already have tested it and nothing happened. I mean that nothing was written to the eeprom. Reason for that i think is this confusing statement:
if(i==4)
i=0;
or
if(i==5)
i=0;
or
if(i==6)
i=0;
EDIT:That was my first idea:to count to 4 for example, write eeprom and after some time to reset i(i=0). I don't know how to do it. |
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Gabriel
Joined: 03 Aug 2009
Posts: 1067
Location: Panama
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| Posted: Fri Sep 07, 2012 9:33 am |
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post your entire test code... should be a small program.
are you sure your eeprom writing function works?
or your reading eeprom function?
PIC number, Compiler number... more details...
im not really trusting this:
| Code: | | write_int16_eeprom(u4,0); |
"u4" is not a hex number thus not an address.... im assuming thats the address since id does not change in your statements...
i might be missing somthing...
proper debounce needs to be implemented....
what is your input circuit....
as for software logic... i think the last one i posted for you should work....
_________________
CCS PCM 5.078 & CCS PCH 5.093 |
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tonkostz
Joined: 07 May 2011
Posts: 40
Location: Bulgaria
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| Posted: Fri Sep 07, 2012 10:24 am |
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This is my program for testing. Input pin A5 is has a pull down resistor an the button is connected between the pin and +5V.
| Code: | #include <12f683.h>
#fuses INTRC_IO,NOWDT,NOMCLR,NOBROWNOUT
#use delay(int=4000000)
#define U4 15
int8 k=0;
int16 data;
void write_int16_eeprom(address, int16 data)
{
int8 i;
for(i = 0; i < 2; ++i)
{
write_eeprom(address + i, *((int8 *)(&data) + i));
}
}
int16 read_int16_eeprom(address)
{
int8 i;
int16 data;
for(i = 0; i < 2; ++i)
{
*((int8 *)(&data) + i) = read_eeprom(address + i);
}
return(data);
}
void main()
{
while(true)
{
if(input(PIN_A5)==1)
{
k++;
if(k>6)
k=6;
while(input(PIN_A5)) //loop here until button released.
{
delay_ms(20);
}
if(k==4)
{
write_int16_eeprom(U4,0);
k=0;
}
if(k==5)
{
write_int16_eeprom(U4,1);
k=0;
}
if(k==6)
{
write_int16_eeprom(U4,2);
k=0;
}
}
}
}
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tonkostz
Joined: 07 May 2011
Posts: 40
Location: Bulgaria
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| Posted: Fri Sep 07, 2012 12:57 pm |
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Finally i managed to make exactly what i wanted.
This is the full code:
| Code: | #include <12f683.h>
#fuses INTRC_IO,NOMCLR,NOBROWNOUT
#use delay(int=4000000)
#define DEBOUNCE_PERIOD_IN_MS 100
#define TIMEOUT 20
#define U4 15
int8 k=0;
int16 data;
void write_int16_eeprom(address, int16 data)
{
int8 i;
for(i = 0; i < 2; ++i)
{
write_eeprom(address + i, *((int8 *)(&data) + i));
}
}
int16 read_int16_eeprom(address)
{
int8 i;
int16 data;
for(i = 0; i < 2; ++i)
{
*((int8 *)(&data) + i) = read_eeprom(address + i);
}
return(data);
}
void main()
{
int8 count=0;
while(true)
{
if(input(PIN_A5)==1)
{
count=0;
k++;
if(k>6)
k=0;
while(input(PIN_A5)) //loop here until button released.
{
delay_ms(15);
}
}
else
{
count++;
}
if(count == TIMEOUT)
{
if(k==4)
{
write_int16_eeprom(U4,1);
k=0;
}
if(k==5)
{
write_int16_eeprom(U4,2);
k=0;
}
if(k==6)
{
write_int16_eeprom(U4,3);
k=0;
}
}
data=read_int16_eeprom(U4);
if(data==1)
{
output_high(PIN_A2);
}
if(data==2)
{
output_high(PIN_A2);
delay_ms(50);
output_low(PIN_A2);
delay_ms(50);
}
if(data==3)
{
output_high(PIN_A2);
delay_ms(200);
output_low(PIN_A2);
delay_ms(200);
}
delay_ms(DEBOUNCE_PERIOD_IN_MS);
}
} |
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