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I am lost the embedding data EEPROM

 
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pilar



Joined: 30 Jan 2008
Posts: 197

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I am lost the embedding data EEPROM
PostPosted: Wed Nov 11, 2009 2:30 pm     Reply with quote
Hi, I am use the #ROM preprocessor directive to embedding data EEPROM during programming the pic18f452, but when I want to to read this data, it simply altered or lost, there is something I am forgetting?

Code:
#rom int8 0xf00001 = {"21"}
#rom int8 0xf0002D = {"OFF"}         
#rom int8 0xf00039 = {"00:10:00"}


But when I do the simulation using the proteus everything is OK
PCM programmer



Joined: 06 Sep 2003
Posts: 21708

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PostPosted: Wed Nov 11, 2009 2:51 pm     Reply with quote
Post a very short, compilable test program that shows the problem.

Post your compiler version.
Guest
PostPosted: Wed Nov 11, 2009 3:52 pm     Reply with quote
Hi PCM programmer, here is my code:

Code:
#include <18F452.h>
#fuses HS,NOWDT,NOPROTECT,NOLVP,NOBROWNOUT
#use delay(clock=20000000)
#use rs232(baud = 9600, xmit=PIN_C6, rcv=PIN_C7)// RS232 Estándar

int i;

#rom int8 0xf00001 = {"21"}
#rom int8 0xf0002D = {"OFF"}         
#rom int8 0xf00039 = {"00:10:00"}

void main(){
char buffer [8];

   for (i = 0 ; i<8 ; i++)
      buffer[i] = read_eeprom(57+i);
   printf("%s ",buffer);

while (true);
}
PCM programmer



Joined: 06 Sep 2003
Posts: 21708

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PostPosted: Wed Nov 11, 2009 3:58 pm     Reply with quote
What's a string ? Look at a FAQ:
http://www.macdonald.egate.net/CompSci/hstrings.html
He says:
Quote:

In C, a string is stored as a null-terminated char array.
This means that after the last truly usable char there is
a null, hex 00, which is represented in C by '\0'.


Look at your code:
Quote:

#rom int8 0xf00039 = {"00:10:00"}

char buffer [8];

for (i = 0 ; i<8 ; i++)
buffer[i] = read_eeprom(57+i);
printf("%s ",buffer);

Your string buffer doesn't have room for the 0x00 at the end,
and you don't put it there. It's not a string.
pilar



Joined: 30 Jan 2008
Posts: 197

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PostPosted: Fri Nov 13, 2009 8:04 am     Reply with quote
Embarassed You're right
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