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Very weird RTCC, InT_RDA, and delay_ms problem

 
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evsource



Joined: 21 Nov 2006
Posts: 129

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Very weird RTCC, InT_RDA, and delay_ms problem
PostPosted: Mon Feb 23, 2009 4:46 pm     Reply with quote

I'm wondering if someone else can duplicate this error.

I'm using PCH 4.030, 18F2620.

If I put a delay in the INT_RDA ISR, or a delay in main's while loop, then timing for timer0 is messed up by a factor of about 18 or 20.

Here's the code. I tried to strip out everything that wasn't needed, but it's still sort of long. Basically, I just have the RTCC ISR turning on and off a LED. You're probably saying "don't put a delay in an ISR you dummy!" ... I know, I'm not looking for code guidance, just trying to understand why the delay is affecting the timing, especially when INT_RDA isn't even turned on! What's more interesting is that if *either* delay (in INT_RDA or main) is commented out, then the timing works correctly. Very weird!

Code:

#include <18f2620.h>
#device ADC=10 // use 10 bit ADC reading
#fuses HS,WDT256,NOMCLR,NOWDT,NOPROTECT,NOBROWNOUT,BORV21,NOPROTECT,NOLVP
#use delay(clock=20000000)
#use rs232(baud=115200, xmit=PIN_C6, rcv=PIN_C7, errors)

#int_rda
void serial_isr() {
     delay_ms(100);  // comment this out, and timing for timer0 works correctly
}

/* !!!!!!!!  LED functions, defines, and variables !!!!!!!! */
#define SLOW_FLASH 1 // transition every second
#define NO_FLASH 0
#define INTS_PER_SECOND 76     // (20000000/(4*256*256))
#define BLUE_LED_PIN PIN_C4

void blue_LED_on(int1);
void toggle_blue_LED();
void check_LEDs(int);

// Number of interrupts left before a second has elapsed
BYTE int_count1;

// variables to store current state of LED
int1 blue_LED;
int blue_flashrate;

#int_rtcc
void clock_isr() {
     if(--int_count1==0) {
          check_LEDs(SLOW_FLASH);
          int_count1=INTS_PER_SECOND;
     }
}
/* !!!!!!!!  END LED functions, defines, and variables !!!!!!!! */

void main() {
     setup_adc(  ADC_CLOCK_INTERNAL  );
     setup_adc_ports( ALL_ANALOG );

     enable_interrupts(INT_RTCC);
     enable_interrupts(GLOBAL);

     /* setup counter parameters */
     int_count1=INTS_PER_SECOND;
     setup_timer_0( RTCC_INTERNAL | RTCC_8_BIT | RTCC_DIV_256);
     set_timer0(0);
     /* end setup on counter parameters */

     blue_LED = FALSE;
     blue_LED_on(FALSE);
     blue_flashrate = SLOW_FLASH;

     setup_wdt(WDT_ON); // WDT on in software

     while(1) {
          printf("Hi\r\n");
    //      delay_ms(500);  // comment this out, and timing for timer0 works correctly
          restart_wdt();
     }
}

/********************* Functions **************************/
void check_LEDs(int rate) {
     if(blue_flashrate == rate) {
          toggle_blue_LED();
     }
}

void blue_LED_on(int1 on) {
     if(on) output_low(BLUE_LED_PIN);
     else output_high(BLUE_LED_PIN);
}

void toggle_blue_LED() {
     blue_LED = !blue_LED;
     blue_LED_on(blue_LED);
}
PCM programmer



Joined: 06 Sep 2003
Posts: 21708

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PostPosted: Mon Feb 23, 2009 5:26 pm     Reply with quote

If you have both delay_ms() statements in your program, you'll get a
"re-entrancy" warning message. To fix that, you can create another
instance of the delay library code by adding the line shown in bold below
just above main():
Quote:
#use delay(clock=20000000)
void main() {

Then the interrupt routine will have it's own dedicated delay routine,
and the main code will another it's own routine. Their won't be any
re-entrancy issues and the compiler won't disable interrupts while the
delay_ms() statement in main() is running.
dyeatman



Joined: 06 Sep 2003
Posts: 1934
Location: Norman, OK

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PostPosted: Mon Feb 23, 2009 6:02 pm     Reply with quote

Also, if the #int_rda is enabled you will have another
problem. Without a getc() in the interrupt routine to clear
the interrupt, the interrupt will not be cleared and it will be
called repeatedly which will cause the program to stay in the
#int_rda delay_ms() almost continously.
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