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Passing a string to a buffer error?

 
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BlueTower



Joined: 23 Oct 2008
Posts: 29

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Passing a string to a buffer error?
PostPosted: Thu Nov 27, 2008 4:39 am     Reply with quote
Hi all. I have the following function:

Quote:

void Serial_RD(void)
{
#asm //Copy the Serial Number from the EEPROM Buffer (var_table)
MOVF var_table+2, 0 //High value (var_table[2])
MOVWF convInt24
MOVF var_table+3, 0 //Mid value (var_table[3])
MOVWF convInt24+1
MOVF var_table+4, 0 //Low value (var_table[4])
MOVWF convInt24+2
#endasm
CV_Int24ToStr(); //Convert to string (returns in convString)

cfgStringBuf = "#RI="; //Build the Output String
for (i = 0; i < 8; i++)
cfgStringBuf[i + 4] = convString[i];
cfgStringBuf[12] = 13;
CFG_WriteData(); //Write out via RS-232
}


and cfgStringBuf is declared as :
Quote:

unsigned char cfgStringBuf [20]; //String Buffer


I got Error 49:'Expecting LVALUE such as a variable name or * expression' in line cfgStringBuf = "#RI=";
Any ideas why?

Regards
Ttelmah
Guest
PostPosted: Thu Nov 27, 2008 5:18 am     Reply with quote
strcpy(cfgStringBuf,"#RI=");

Two 'parts' to this. The first is 'standard C'. A string, is not a 'type', but an array of characters. Initialising with a string, involves moving the whole array. C allows this for the declaration of a variable, but not 'inline' as you show. However most 'latter variants' (C++ etc.), allow an inline initialisation like this. Unfortunately on the PIC, there is a problem. Because the 'constant' data is stored as part of the program memory space, and not as part of the RAM, you can't construct a pointer to the RAM, to perform the initialisation. Strcpy, has an 'overloaded' version of itself, that accepts a constant, and performs the data movement required.

Best Wishes
BlueTower



Joined: 23 Oct 2008
Posts: 29

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PostPosted: Thu Nov 27, 2008 7:24 am     Reply with quote
Thanks for quick reply. I am now facing the following problem:

I want to convert a 32-bit unsigned integer to a string.

I haven't found a suitable function in stdlib.h file. Any ideas ?
Ttelmah
Guest
PostPosted: Thu Nov 27, 2008 10:10 am     Reply with quote
sprintf

Basically you 'print' the variable to a string.

Best Wishes
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