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Arael83
Joined: 23 Jun 2008
Posts: 3
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| problem with #INT_EXT, #INT_EXT1 and #INT_EXT |
 Posted: Mon Jun 23, 2008 2:02 am |
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hi, I want make and example to use RB0, RB1 and RB2, RB0 works good but RB1 and RB2 doesn't work. I don't know what is the problem. My program is a cronometer, RB0 start the time, RB1 use a lap aplication keeping the time on display when recive a another interrupt on RB1 and RB2 only start the time same RB0.
| Code: | #include <18F4520.h>
#fuses XT,NOWDT,NOPROTECT, NOLVP, NOBROWNOUT, PUT, NOWRT
#use delay(clock=4000000)
#use fast_io(D)
//#use i2c(MASTER, SDA=PIN_C4, SCL=PIN_C3, ADDRESS=0xa0, SLOW, FORCE_HW)
#byte port_a=0x05
#byte port_b=0x06
#byte port_d=0x08
int min1=0, min2=0, seg1=0, seg2=0, valor=1, i, estado, show=0, tempm1, tempm2, temps1, temps2;
int m1,m2,s1,s2;
unsigned int CONST DISPLAY[10]={0x7E, 0x0C, 0xB6, 0x9E, 0xCC, 0xDA, 0xFA, 0x0E, 0xFE, 0xDE};
/*---------------------------------------------------------------------*/
void mostrar()
{
if(show<1)
{m1=min1; m2=min2; s1=seg1; s2=seg2;}
if(show==1)
{m1=tempm1; m2=tempm2; s1=temps1; s2=temps2;}
output_D(DISPLAY[m1]);
output_high(PIN_A0);
delay_ms(12);
output_low(PIN_A0);
output_D(DISPLAY[m2]);
output_high(PIN_A1);
delay_ms(12);
output_low(PIN_A1);
output_D(DISPLAY[s1]);
output_high(PIN_A2);
delay_ms(12);
output_low(PIN_A2);
output_D(DISPLAY[s2]);
output_high(PIN_A3);
delay_ms(12);
output_low(PIN_A3);
return;
}
/*----------------------------------------------------------------------*/
void retraso()
{
for(i=1;i<=10;++i)
{
mostrar();
delay_ms(10);
}
return;
}
/*----------------------------------------------------------------------*/
void conversion()
{
do
{
do
{
do
{
do
{
mostrar();
retraso();
seg2=seg2+1;
}while(seg2<10);
seg2=0;
seg1=seg1+1;
}while(seg1!=6);
min2=min2+1;
seg1=0;
}while(min2<10);
min2=0;
min1=min1+1;
}while(min1!=6);
}
/*---------------------------------------------------------------------*/
#int_EXT
void EXT_ISR(void)
{
conversion();
/* tempm1=min1, tempm2=min2, temps1=seg1, temps2=seg2;
show=1;
valor++;
if(valor%2 && valor>1)
{show=0;}
*/
}
#int_EXT1
void EXT1_ISR(void)
{
tempm1=min1, tempm2=min2, temps1=seg1, temps2=seg2;
show=1;
valor++;
if(valor%2 && valor>1)
{show=0;}
}
#int_EXT2
void EXT2_ISR(void)
{
conversion();
}
/*---------------------------------------------------------------------*/
void main()
{
set_tris_a(0xF8);
set_tris_d(0x00);
port_a=0x00;
port_d=0x00;
enable_interrupts(global);
enable_interrupts(INT_EXT);
enable_interrupts(INT_EXT1);
enable_interrupts(INT_EXT2);
enable_interrupts(INT_RB);
ext_int_edge( L_TO_H );
ext_int_edge(1,L_TO_H );
ext_int_edge(2,L_TO_H );
min1=0, min2=0, seg1=0, seg2=0;
/*do
{
conversion();
}while(1);
}*/
}
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I using CCS 3.216 |
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Ttelmah
Guest
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| Posted: Mon Jun 23, 2008 4:24 am |
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Your problem is that the first interrupt is taking so long.
You have the 'mostrar' routine, taking something over 48mSec, called repeatedly in this. The whole time you are doing this, no other interrupt can be serviced.
Do a search here. The general rule for handling interrupts, is keep the handler _short_. You should just set a flag in the interrupt, and have the 'main' code perform the display update, when it see this flag. The internal values (min1 etc.,) are also never reset after the first time in the main. Once they climb past their 'test' values, they are going to have to count all the way 'round', to get back to the starting point. This will result in the inner loop being called several million times. The code then spends _ages_ in this loop, never allowing time to handle the other interrupts.
You also have the problem of trying to call the same routines inside, and outside the interrupts. Though you have this 'remmed' out at present, this will result in interrupts being disabled in this routine in the external code, and make things even worse...
Best Wishes |
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Arael83
Joined: 23 Jun 2008
Posts: 3
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| I make more easy but nothing happend |
| Posted: Mon Jun 23, 2008 7:20 pm |
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I erase the loop, only try to display several number on displays, #INT_EXT works fine, but my another interrupts on #INT_EXT1 and #INT_EXT2, doesn't work. I was use Oshon PIC18 2.55 and see my RB1-RB4, configured as analog. I don´t know what happend. my code its here
| Code: | #include <18F4520.h>
#fuses XT,NOWDT,NOPROTECT, NOLVP, NOBROWNOUT, PUT, NOWRT
#use delay(clock=4000000)
#use fast_io(D)
#byte port_a=0x05
#byte port_b=0x06
#byte port_d=0x08
setup_adc_ports(NO_ANALOGS);
setup_adc(ADC_OFF);
int min1=0, min2=0, seg1=0, seg2=0, valor=1, estado, show=0, tempm1, tempm2, temps1, temps2;
int m1,m2,s1,s2, start, i;
unsigned int CONST DISPLAY[10]={0x7E, 0x0C, 0xB6, 0x9E, 0xCC, 0xDA, 0xFA, 0x0E, 0xFE, 0xDE};
/*---------------------------------------------------------------------*/
void mostrar()
{
if(show<1)
{m1=min1; m2=min2; s1=seg1; s2=seg2;}
if(show==1)
{m1=tempm1; m2=tempm2; s1=temps1; s2=temps2;}
output_D(DISPLAY[m1]);
output_high(PIN_A0);
delay_ms(10);
output_low(PIN_A0);
output_D(DISPLAY[m2]);
output_high(PIN_A1);
delay_ms(10);
output_low(PIN_A1);
output_D(DISPLAY[s1]);
output_high(PIN_A2);
delay_ms(10);
output_low(PIN_A2);
output_D(DISPLAY[s2]);
output_high(PIN_A3);
delay_ms(10);
output_low(PIN_A3);
return;
}
/*----------------------------------------------------------------------*/
void retraso()
{
for(i=1;i<=10;++i)
{
mostrar();
delay_ms(10);
}
return;
}
/*---------------------------------------------------------------------*/
#int_EXT
void EXT_ISR(void)
{
min1=0, min2=1, seg1=0, seg2=1;
}
#int_EXT1
void EXT1_ISR(void)
{
min1=2, min2=0, seg1=2, seg2=0;
}
#int_EXT2
void EXT2_ISR(void)
{
min1=3, min2=3, seg1=3, seg2=3;
}
/*---------------------------------------------------------------------*/
void main()
{
set_tris_a(0x00);
set_tris_d(0x00);
set_tris_b(0xFF);
port_a=0x00;
port_d=0x00;
port_b=0x00;
enable_interrupts(INT_EXT);
enable_interrupts(INT_EXT1);
enable_interrupts(INT_EXT2);
enable_interrupts(global);
ext_int_edge(0, L_TO_H );
ext_int_edge(1,L_TO_H );
ext_int_edge(2,L_TO_H );
min1=0, min2=0, seg1=0, seg2=0;
do
{
mostrar();
}while(1);
} |
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PCM programmer
Joined: 06 Sep 2003
Posts: 21708
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| Posted: Mon Jun 23, 2008 7:45 pm |
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| Quote: |
#include <18F4520.h>
#byte port_a=0x05
#byte port_b=0x06
#byte port_d=0x08
port_a=0x00;
port_d=0x00;
port_b=0x00;
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Download the 18F4520 data sheet.
http://ww1.microchip.com/downloads/en/DeviceDoc/39631D.pdf
Look in the following section and fix the register addresses
for Ports A, B, and D.
| Quote: | | TABLE 5-1: SPECIAL FUNCTION REGISTER MAP FOR PIC18F2420/2520/4420/4520 DEVICES |
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