round numbers

[spom]

Hi,
how can I round numbers, so that 10.3 is 10 and 10.7 is 11?
abs() returns always 10.

Thanks!

[Ttelmah]

Abs, just removes the sign. If you are getting '10', it is not because of 'abs' at all, but because you are putting the result into an integer, which removes the fractional part. Abs on it's own, won't do this...
Now, question is whether you need to handle -ve numbers as well?.
For +ve numbers:

result = (int16)(val+0.499999);

Will give normal 4/5 rounding, assuming the result will fit in an int16.

For full numeric range:

result = (signed int32)((val>0.0)?(val+.4999999):(val-0.4999999));

Will work for the entire range of a signed int32.

So, generating a declare for this:
#define round45(x) (signed int32)((x>=0.0)?(x+.4999999):(x-0.4999999))

will allow you to have:

result = round45(val);

and should do what you want.

Best Wishes