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adc pic16f877a not has stopped working!

 
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kein



Joined: 23 Jul 2007
Posts: 103

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adc pic16f877a not has stopped working!
PostPosted: Fri Sep 07, 2007 8:10 am     Reply with quote

The following codes prints zero even when Vref+ is set to vdd(5v) and vref- set to ground(vss). why isn't it working? any idea?
Thanks

Code:
#include <16F877A.h>
#device *=16
#device adc=10
#FUSES NOWDT                    //No Watch Dog Timer
#FUSES HS                       //High speed Osc (> 4mhz)
#FUSES NOPUT                    //No Power Up Timer
#FUSES NOPROTECT                //Code not protected from reading
#FUSES NODEBUG                  //No Debug mode for ICD
#FUSES NOBROWNOUT               //No brownout reset
#FUSES NOLVP                    //No low voltage prgming, B3(PIC16) or B5(PIC18) used for I/O

#use delay(clock=20000000)
#use rs232(baud=9600,parity=N,xmit=PIN_C6,rcv=PIN_C7,bits=8)

#include <KBD.C>
#include <ctype.h>
#include <float.h>
#include <math.h>
#include <string.h>
#include "LCD.c"

void main()
{

   long int adcValue;                    // 16-bit storage for ADC reading
 
   lcd_init();
 
   setup_adc_ports(AN0_AN1_AN4_AN5_VREF_VREF);
   setup_adc(ADC_CLOCK_DIV_32);;
   setup_adc(ADC_OFF);   
   lcd_goto_xy(1,1);                  // Type some characters and backspace   over them.
   lcd_put_c(" X      Y      Z");
   
   delay_Ms(1000); 

   
   // TODO: USER CODE!!
   while(1)
   {
      //AccelCalibrateXYZ();
       set_adc_channel(0);            // select the required channel
       delay_us(10);
       adcValue =read_adc();

       lcd_gotoxy(13,2);
       printf(lcd_putc, "%Lu ", adcValue);
      delay_ms(200); 
   }
     //return 0;

}
Foppie



Joined: 16 Sep 2005
Posts: 138
Location: The Netherlands

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PostPosted: Fri Sep 07, 2007 8:23 am     Reply with quote

try commenting out the following line in your code:
Code:
setup_adc(ADC_OFF);

That might solve your problem
kein



Joined: 23 Jul 2007
Posts: 103

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it did solve the problem
PostPosted: Fri Sep 07, 2007 9:57 am     Reply with quote

it did solve the problem; thanks
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