out of rom?

[ss1903]

hi
i have a problem with 16f877A -8K word flash memory.

in my code, i got out of rom error while it used only about %42 of rom.

so i wrote a simple code how much i could use all of the rom.


#include <16F877A.h>

#fuses HS,NOWDT,NOPROTECT,NOLVP
#use delay(clock=4000000)

float a=999999;
float b=1.1;

void main()
{
a=a/b;
a=a/b;
a=a/b;
.
.
.
.
a=a/b;
}

the number of a=a/b is 75 and rom usage is %27.
after I added a=a/b
and i got out or rom error.

do you have an idea how can i achieve this problem?

[Guest]

How about searching the forum, before asking?...
Or even reading the manual?...
You are not running out of ROM as such, but running out of space in one 'segment'. A search on the forum, will find a full description, as well as what you can do about it. It is also detailed in the compiler manual.

Best Wishes

[ss1903]

dear guest
thank for reply.
i examined compiler manual and it say you must use #separete before function. but in this code i didnt use function. there is only divison. i think this divison is built in function. so how can i use #separete in this state.
i've been searching the forum but yet i cant find the solution.

[Ttelmah]

You have to split your code up....

Best Wishes

[rnielsen]

Read this post:

http://www.ccsinfo.com/forum/viewtopic.php?t=30167&