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Using a union inside a struct

 
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NathanI
Guest
Using a union inside a struct
PostPosted: Fri Feb 16, 2007 1:30 pm     Reply with quote
Hi, I did a forum search, but didn't find anything that matched my question. Basically I want to do this:

typedef union _CALDATA
{
unsigned int16 word;
signed int16 sword;
struct
{
byte L;
byte H;
} BYTES;

} CALDATA;

typedef struct
{
CALDATA minVal;
CALDATA maxVal;
CALDATA curVal;
} MINMAXCAL;

This compiles fine, but when I reference it by doing this:

myVarArray[5].minVal.word = 0x0000;

Compiler says
*** Error 57 "**Location**" Line 753(37,43): Expecting a structure/union

Please let my know if this is possible, thanks in advance.

P.S. I am using compiler version 3.184 and I replace my directory with **Location**.
Ttelmah
Guest
PostPosted: Fri Feb 16, 2007 4:12 pm     Reply with quote
I don't see any actual declaration of 'MyVarArray'.
It compiles fine on 3.163, 1nd 3.191 (the two nearest versions I have to 3.184), with:
Code:

// First declare the data type
typedef union {
   unsigned int16 word;
   signed int16 sword;
   struct {
      byte L;
      byte H;
   } BYTES;
} CALDATA;

//Now a structure of these types
typedef struct {
  CALDATA minVal;
  CALDATA maxVal;
  CALDATA curVal;
} MINMAXCAL;

//Now declare the array
MINMAXCAL MyVarArray[10];

void main() {

   setup_adc_ports(NO_ANALOGS);
   setup_adc(ADC_OFF);
   setup_psp(PSP_DISABLED);
   setup_spi(FALSE);
   setup_timer_0(RTCC_INTERNAL|RTCC_DIV_1);
   setup_timer_1(T1_DISABLED);
   setup_timer_2(T2_DISABLED,0,1);
   //Now access the array
   MyVarArray[5].minVal.word=0x0L;
}

This correctly uses 60 bytes, and the list shows the correct 16bit word being accessed.

Best Wishes
Guest
PostPosted: Fri Feb 16, 2007 5:14 pm     Reply with quote
Wow, yeah sorry for wasting your time. I had declared it not as an array. Forgot to adjust my temp variable.
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