how to output a 16bit value to two 8 bit ports

[brood]

Hi

I would like to know if its possible to output a 16bit value to two 8 bit ports and how to do it. The pic that I'm using is: pic16f917

My aim is to control 16 led's connected to port A and port B with a single hex value. I was successful with controlling port A with a single hex value.

here is my setup code with two code arrays:

#include <16F917>
#fuses INTRC_IO,NOPROTECT,NOWDT,PUT
#use delay(clock=8000000)
#use standard_io(a)
#use standard_io(b)
#use standard_io(c)
#use standard_io(d)
#case

const unsigned int A[10] = {0xFFF8, 0xFFFC, 0x0186, 0x0183, 0x0181, 0x0181, 0x0183, 0x0186, 0xFFFC, 0xFFF8}; //A

const unsigned int a[5] = {0x7C, 0x12, 0x11, 0x12, 0x7C}; //a

void main()
{
setup_lcd(LCD_DISABLED); // disables lcd display to access digital outputs
for (;;)
{
delay_ms(1000);
output_a(a[0]); // 1st line of a
}

}

[SherpaDoug]

How about using make8() to split the bytes, and dealing with each byte seperately?
_________________
The search for better is endless. Instead simply find very good and get the job done.

[brood]

I think that might just do the trick

Thank you very much

[treitmey]

you could also try fastio.
set the tris.
use a #byte to define where it is placed.
((or overlayed, how ever you want to think of it))
It uses the location and the next. ie: portA and port B

[mrpicing]

you can do it as below.

[brood]

Thank you for all the replies it solved lots of problems that I had. Everything is up and running now. I used make8() in the end and passed two 8bit values to my output function.